Here is my code at the moment:

import java.util.Scanner;

class menuOperations
{
	String[] fNames = new String[50];
	String[] lNames = new String[50];

	String fName = " ";
	String lName = " ";

	String sFName = " ";
	String sLName = " ";

	int dAmount,dTimes,i;

	Scanner in = new Scanner(System.in);


	public void newEntry()
	{
		if (fName == " ")
		{
			int i = 0;
		}


		if (i == 50)
		{
			System.out.println("Sorry, your address book is full.  You can only store 50 entires per book.");
		}

		else
		{
			System.out.println("Please enter the first name of the person:");
			fName = in.nextLine();

			fNames[i] = fName;

			if (fNames[i] != fName)
			{
				System.out.println("There was a probelm entering the name.");
				}

				else
				{
					System.out.println("The name was entered successfully.");
					i += 1;

			}
		}
	} //End newEntry

	public void search()
	{
		System.out.println("Please enter the name you wish to search for, first or last name ONLY");
		sFName = in.nextLine();

		System.out.println(sFName);

		for (int j = 0; j < fNames.length; j++)
		{
			if (fNames[j] == sFName)
			{
				System.out.println(fNames[j]);
			}
		}
	} //End search

}





public class it215_w2_addressbook
{

	public static void main(String[] args)
	{
		//String fName,lName;
		//int dAmount,dTimes;
		int uChoice;
		boolean quit = false;

		Scanner in = new Scanner(System.in);
		menuOperations mO = new menuOperations();


		System.out.println("Welcome to your Electronic Address Book, or EAB.");

		while (!quit)
		{
			System.out.println("Please choose an option from the following menu:");

			System.out.println("1) New Entry");
			System.out.println("2) Search");
			System.out.println("3) Display All");
			System.out.println("4) Load Address Book");
			System.out.println("5) Quit Program and Save Address Book");

			System.out.printf(">");

			uChoice = in.nextInt();

			switch (uChoice)
			{
				case 2:
				{
					mO.search();
					break;
				}

				case 5:
				{
					quit = true;
					break;
				}


				default:
				{
					mO.newEntry();
					break;
				}
			}
		}
	}
}

So, now my main problem is in the search method. At the for loop at the end the code should take the entered name, which I have verified is saved correctly via the system.out line, and then search the array for matching names and print them.

When I run the program, however, it does now print out these array elements. So far, everything I have found on google states that the print command used should work.

working in:

java version "1.6.0_23"
Java(TM) SE Runtime Environment (build 1.6.0_23-b05)
Java HotSpot(TM) Client VM (build 19.0-b09, mixed mode, sharing)

Recommended Answers

All 2 Replies

I don't understand your question, What are you trying to do?

After some additional testing, I found that Java is slightly different from C++, my first language. You can not compare strings with the == operator, doh. I switched that to .equals and bingo, it works.

@Akill10

This is an assignment for a class. We are supposed to make an address book that the user can enter entries, search for a specific entry, and be able to save the address book. I was trying to figure out a way to search for a specific name via iterating one of the name arrays and looking for any elements with that specific name.

Problem was as stated above.

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