'else" without a previous 'if' ERROR

[M1n1m@l1$t]

The following is the code for my program that is supposed to choose a random number and then get the user to guess it by using the basic hints. It seems like it should work but it keeps coming up with the error:'else' without a previous 'if'. it is getting really annoying. Hope someone can help.

#include <iostream>
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
using namespace std;

int main()
{
    int secretnum;
    int getint;

    srand (time(NULL) );

    secretnum=rand() % 10;

    cout<<"guess a number between 1 and 10_";
    cin>>getint;

        if (secretnum<getint)
            cout<<"try a lower number";
            goto loop;
        else if (secretnum>getint)
            cout<<"try a higher number";
            goto loop;
        else
            cout<<"that is correct";
        loop:
            cout<<"Enter another number between 1 and 10_";
            cin>>getint;

    return 0;
}

I am using code::blocks. I hope its not to abvious i have only been programming for a couple weeks.

thanks

[Narue]

Until you know the rules for braces, it's best to always use them:

if (secretnum<getint)
{
    cout<<"try a lower number";
    goto loop;
}
else if (secretnum>getint)
{
    cout<<"try a higher number";
    goto loop;
}
else
{
    cout<<"that is correct";
}

By the way, you should also avoid goto in favor of explicit loop structures, especially when starting out.

[ichigo_cool]

You need to use braces if within the if (conditional) you have more than a single line.

...Does not require braces...
if (age>18)
cout << "You may enter the bar";

...Requires braces...
if (age < 18)
{
cout << "You're too young.";
return 0;
}

[ichigo_cool]

Also, try never to use 'goto', most of the time you can use a 'while loop' instead.

[M1n1m@l1$t]

thanks for the help that error is now gone but when i run the program it always chooses the number 5 (i tested it quite a few times). I tried recompiling but it was still wrong.

[m4ster_r0shi]

Could you post your code again?

[M1n1m@l1$t]

yeah i can post my new code here it is:

#include <iostream>
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
using namespace std;

int main()
{
    int secretnum;
    int getint;

    srand (time(NULL) );

    secretnum=rand() % 10;

    loop:
    cout<<"guess a number between 1 and 10_";
    cin>>getint;

        if (secretnum<getint)
        {
            cout<<"try a lower number";
            goto loop;
        }

        else if (secretnum>getint)
            {
                cout<<"try a higher number";
               goto loop;
            }
        else
            {
                cout<<"that is correct, press enter to end";
            }





    return 0;
}

[m4ster_r0shi]

It works ok for me. Maybe you should just try playing more. Here, I made a couple of modifications:

#include <iostream>
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
using namespace std;

int main()
{
    int secretnum;
    int getint;

    srand(time(NULL));

    again:

    secretnum = rand() % 10 + 1;

    loop:

    cout<<"guess a number between 1 and 10_";
    cin>>getint;

    if (secretnum<getint)
    {
        cout<<"try a lower number";
        goto loop;
    }
    else if (secretnum>getint)
    {
        cout<<"try a higher number";
        goto loop;
    }
    else
    {
        cout<<"that is correct. play again? <y/n>\n";

        char choice;
        cin >> choice;

        if (choice == 'y' || choice == 'Y')
            goto again;

        cout << "press enter to end";
    }

    return 0;
}

Notice that rand() % 10 will give a random number between 0 and 9. You need to add one to get a [1, 10] range.