How many vowels, consonants, punct., and spaces

[babi.meloo]

I need to design an application that reads a string from the user, then determines and prints
how many of each lowercase vowel appear in the entire string. Separate counter for each vowel.
I also need to count and print the number of consonants, spaces, and punctuation marks.

The problem I'm having with my code is that the consonants counter won't work. It gives me the wrong number. The rest works perfectly fine.

import java.util.*;

public class Vowel14
{
    public static void main (String[] args) 
    {
        Scanner scan = new Scanner(System.in);

        int letA = 0, letE = 0, letI = 0, letO = 0, letU = 0;
        int cons = 0, spc = 0, punc = 0; 

        System.out.print("Enter a string: ");
        String input = scan.nextLine();

        for ( int i=0; i < input.length(); i++ )
        {
            char ch = input.charAt(i);
            ch = Character.toLowerCase(ch);
            if ( 'a' == ch )
                letA++;
            if ( 'e' == ch ) 
                letE++;
            if ( 'i' == ch ) 
                letI++;
            if ( 'o' == ch )
                letO++;
            if ( 'u' == ch )
                letU++;
            if ('a' != ch && 'e' != ch && 'i' != ch && 'o' != ch && 'u' != ch)
                cons++;
            if ( '.' == ch || ',' == ch || '-' == ch || '!' == ch || '?' == ch || '_' == ch)
                punc++;
            if ( ' ' == ch)
                spc++;
        }
        System.out.println("There are " + input.length() + " characters total.\n" +
            "Vowels:\n" +
            "A's : " + letA + "\n" +
            "E's : " + letE + "\n" +
            "I's : " + letI + "\n" +
            "O's : " + letO + "\n" +
            "U's : " + letU);

        System.out.println("There are " + cons + " consonants.");
        System.out.println("There are " + punc + " punctuation marks.");
        System.out.println("There are " + spc + " spaces");

    }
}

[Taywin]

You need if, else if, else statements, not only if. Currently, all punctuations will also be counted as consonent because they are not equal to any vowel. And if you use else if too, your else will cover all consonents (and special characters if you don't care).

PS: I usually use if (ch=='a') instead of if ('a'==ch). Though it could be just a style...