Divisibility Check without using % / +

[sub-zer0]

Hello how can i check the divisibility of a number without using % / +...
I am new at coding so hope someone can help
I think my code sucks ..i read forums and this is the best i can do

import java.util.Scanner;


public class Divbythree {


    public static void main(String[] args) {
        // TODO Auto-generated method stub

        System.out.println("Enter A Number");
        Scanner keyboard =new Scanner(System.in);
        int Numero = keyboard.nextInt();
        int newNumero = Numero;


        while (newNumero > 0){

            newNumero -= 3;
            System.out.println("1");
                //return newNumero == 0;
            }   

        while (newNumero < 0){
            newNumero += 3;
            System.out.println("2");

        }


    }

}

[DarkLightning7]

One way to test if "a" is divisible by "b" simply subtract "b" from "a" until you get a negative number or zero.

You can also test divisiblity using bit operations. To test if something is diisible by 2 do:

if(a & 1 == 0)  //checks if there is a 1 in the last position of the binary number.

to test if something is divisible by 3 you can so something like this:

public boolean divisibleBy3(int n) {
    if (n < 0){
        n = -n;  //if it is a negative number make it posirive otherwise the test will fail
    }else if (n == 0) {
        return true;
    }

    while (n > 3) {
        int d = 0;

        while (n > 0) {
            d += n & 3;  //add last 2 bits of n to d
            n = n >> 2;  //shift n 2 bits to the right
        }

        n = d;
    }

    return n == 3;
}

[somjit{}]

divisibilty ? by what ?

if your looking for odd/even number check you can use bit-wise operations : all even numbers will have 0 in their lowest order bit , whereas odd ones will have 1. check for that , and youll get your answers.

[JeffGrigg]

If I wanted to know if 10 was divisible by 3 without using division, I'd subtract 3 repeatedly:

10 - 3 = 7
7 - 3 = 4
4 - 3 = 1

The remainder is 1 -- a number that is smaller than three, but it's not zero. So 10 is not divisible by 3.

I would probably write a program to do something much like what I just did above.

[cool_zephyr]

while(dividend>0)
    dividend-=divisor;

if(dividend==0) //is divisible;
else //is not divisible;

p.s. put a divide by zero check in the beginning

[sub-zer0]

Thanks everyone for the replies..sorry for the late view here.i already solve it 2days ago..i do something like JeffGrigg does..