When I try to display the address of a char type variable, I don't get the normal hexidecimal address, but some strange symbols. I don't have the same problem with int or string, etc.. Example:
char x='#';
cout << &x;The output of this is: #( (
What's the explanation?
Jump to PostHere's an example discussion about this. Another look and it appears your first line 1 is not correct.
https://stackoverflow.com/questions/17813423/cout-with-char-argument-prints-string-not-pointer-valueTry
char *x='"Test";
Jump to PostIsn't &var the address of any variable var, regardless its type? (or am I missing something?)
Yes, but you are missing something, namely that the cout << operator for a pointer to a char is overloaded so it works well for char arays (used to hold strings in …
Jump to PostYou can cast it so it's not a char pointer, eg
cout << (void*) &x
I see nothing wrong with it spewing seemingly nonsense. Just like any number you have to convert it to a string somehow.
If I change char to int:
int x=6;
cout << &x;The output would be what's expect, an address: 0x28ff0c
You are leaning on your c++ compiler ability to convert a number to ascii. Think back to old C days. Now format it.
As this can be compiler dependent I would not lean on this too hard. Do it like we did in C.
Here's an example discussion about this. Another look and it appears your first line 1 is not correct.
https://stackoverflow.com/questions/17813423/cout-with-char-argument-prints-string-not-pointer-value
Try
char *x='"Test";
Thanks for the link to the relevant thread. As for my Line 1, I don't think it's incorrect. I had x as a char type, not a pointer.
To go further we have to think and read more. To me you are setting the pointer's address to that single character so a pointer would be correct.
rprofitt, thanks for the replies, but please look at my original code again, I didn't have any pointer variable, just a char variable x, and then display its adress "&x". Isn't &var the address of any variable var, regardless its type? (or am I missing something?)
I looked but this is one of those common questions. Should I use a pointer to a single char? I'll write yes. It's not as if you initialized storage and then put the character into that memory location. You are saying "here's a character, now x points at that character." Hence you use the pointer to that string or char.
Isn't &var the address of any variable var, regardless its type? (or am I missing something?)
Yes, but you are missing something, namely that the cout << operator for a pointer to a char is overloaded so it works well for char arays (used to hold strings in C). It's a special case. It's defined to treat it as a pointer to a zero-delimited string. The nonsense you see is the ASCII interpretation of whatever bytes are at that address, up to the next zero.
I see, thanks James. So how to get the hexidecimal address of a char variable?
You can cast it so it's not a char pointer, eg cout << (void*) &x
Thank you!
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