Hello,
I'm trying to plot this function with using this values:
Rh = 9.8
H0 = 0.063
def Thickness_H(H0, r, Rh):
return float(H0)*np.exp(float(r)/float(Rh))
r = np.linspace(0,1, 10)
x =Thickness_H(H0, r, Rh)
plt.plot(r, x)
plt.show()
I'm trying to defind r like what i know but this dose not work, I'm getting this error:
only length-1 arrays can be converted to Python scalars.
may you please help me in this point?
Thank you
Jump to PostTry to remove all the calls to
float(). They are not necessary, and numpy uses its own float type.
Jump to PostI don't understand your question. If you write
return H0*np.exp(r/Rh), the code works and draws a curve, which is almost a straight line (I suppose it is because1/Rhis small).
Try to remove all the calls to float(). They are not necessary, and numpy uses its own float type.
Okay, what about the plot how can I defined r
I don't understand your question. If you write return H0*np.exp(r/Rh), the code works and draws a curve, which is almost a straight line (I suppose it is because 1/Rh is small).
I want to plot this function
H0*np.exp(r/Rh)
I definded it, then I want to plot it, r is different values ? yes you are right I will get exponential curve?
Yes but when u is close enough to 0, exp(u) is close to 1 + u.
Thank you very much
We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.