who can explain this code

[yara1]

hi every one

i find this code

and i read this descreption about it :

code to call function after u click on it

<a href="<?php $_SERVER['PHP_SELF']?>?type=del">
<img src="del.png"/>
</a>

my qidtion : can i know any information about image when i call function using this code

i mean can i know id of the image which user click on it

if my image jpg can i use it with this code

how i use it ??

this part3

if($_GET['type']=="del")
{

//call functions

}

how i use it

:confused:

[Ole Raptor]

The first code is setting the name of the image. Are you keeping your images in a Link database? If you are you can query your db with the $_GET:

$imagename = $_GET['type'];
$imageinfo = mysql_query("SELECT ID FROM Images WHERE Image_Name = '".$imagename."'") or die(mysql_error());
$info=mysql_fetch_array($imageinfo);
$imageid = $info['ID'];

Not really sure what your looking for but that is how you can see the image information. If your wanting to view what user clicked on a specific image thats just another table and a little more code.
Table Image Click:
ID, ImageID, Userid, any other info you want.

//include the code above
$ImageClick = mysql_query("INSERT INTO Image_Click (ImageID, Userid, other fields) VALUES (`".$imageid."`, `".$_SESSION['userid']."`, `".$otherfields."`)") or die(mysql_error());

Then you can query this table and view the users that have clicked on what images and possibly the time or any other info you want to view.

[yara1]

hi

proffessorPC

is that mean i can do that "

<?php

$imageID = $_GET['type'];
mysql_query("DELETE FROM Images WHERE picID= '".$imageID."'") or die(mysql_error());
?>

:
:

code

:
:

<?php

:
:

<a href="<?php $_SERVER['PHP_SELF']?>?type=$row["picId"]">
<img src="$row["link"]"/>
</a>
:
:

?>

is this code will delete image after user clicked on it

[Ole Raptor]

try using this in the image href

echo "<a href='pagename.php?type=$row['PicId']'>";

[nav33n]

Here is the idea.
Pass the id of the image in the query string. <a href='deleteimage.php?id=4'>Delete now </a> Then, in deleteimage.php, get the id, and delete the image.

//connection
$id = mysql_real_escape_string($_GET['id']);
$q = "delete from table where imageid = '$id'"; // if you are storing the image in the table (which is a very bad idea)
mysql_query($q);
//redirect the user back to the image display screen