Hi,
i would like to know if it is possible to pass values from one page to another through an image link? I've have tried to "echo" the values but it seems like the values are not passing into the other page. Any suggestions on how to do it?
regards,
heels
Jump to Postyou can send it through the address
<a href="yourpage.php?info=imageinfo">then on your other page you can grab the info using
$info = $_GET['info'];this will grab whatever info your sending through the link from image.
Jump to Postyou use a form with either get or post method.
once the form is submitted you can access this data by using:
//This is used when form method is get $var = $_GET['input_name']; //This is used when form method is post $var = $_POST['input_name'];input_name is …
Jump to Postpost your code and I will make adjustments and tell you what i did.
Jump to Postthis should do it:
<form action="search.php" method="get"> <input name="txtSearch" type="text" id="txtSearch" size="40" /> <img src="magnifyingGlass.jpg" alt="Search" width="15" height="15" border="0" onclick="javascript:this.form.submit()" /> </form>what i did was change the method of the form to get and added some javascript to make the form submit when the image is …
you can send it through the address
<a href="yourpage.php?info=imageinfo">then on your other page you can grab the info using
$info = $_GET['info'];this will grab whatever info your sending through the link from image.
you can send it through the address
<a href="yourpage.php?info=imageinfo">then on your other page you can grab the info using
$info = $_GET['info'];this will grab whatever info your sending through the link from image.
Yeah, it works :). But i am trying to get the values from the textbox and pass it to another page. How can it be done? Sorry, i am very new to php. Thanks for your help.
you use a form with either get or post method.
once the form is submitted you can access this data by using:
//This is used when form method is get
$var = $_GET['input_name'];
//This is used when form method is post
$var = $_POST['input_name'];input_name is the name of the form element in which you are trying to get info from.
you use a form with either get or post method.
once the form is submitted you can access this data by using:
//This is used when form method is get $var = $_GET['input_name']; //This is used when form method is post $var = $_POST['input_name'];input_name is the name of the form element in which you are trying to get info from.
yeah, tried that. but apparently still passing empty values. is it because you can't pass values through an image link?
post your code and I will make adjustments and tell you what i did.
post your code and I will make adjustments and tell you what i did.
thanks man,
here it is.
<form method="post" action="<?php echo $_SERVER['PHP_SELF'] ?> ">
<input name="txtSearch" type="text" id="txtSearch" size="40" />
<a href="Search.php?txtSearch=<?php echo $txtSearch=$_POST['txtSearch'];?>"><img src="magnifyingGlass.jpg" alt="Search" name="Search" width="15" height="15" border="0" id="Search" /></a>this should do it:
<form action="search.php" method="get">
<input name="txtSearch" type="text" id="txtSearch" size="40" />
<img src="magnifyingGlass.jpg" alt="Search" width="15" height="15" border="0" onclick="javascript:this.form.submit()" />
</form>what i did was change the method of the form to get and added some javascript to make the form submit when the image is clicked (eliminating the link).
you couldn't of done this the way you had because the form must be submitted before you can access those values via $_GET or $_POST arrays.
this should do it:
<form action="search.php" method="get"> <input name="txtSearch" type="text" id="txtSearch" size="40" /> <img src="magnifyingGlass.jpg" alt="Search" width="15" height="15" border="0" onclick="javascript:this.form.submit()" /> </form>what i did was change the method of the form to get and added some javascript to make the form submit when the image is clicked (eliminating the link).
you couldn't of done this the way you had because the form must be submitted before you can access those values via $_GET or $_POST arrays.
oh, i see. but the image button now can't be clicked?! what is happening?
i'm so sorry for the trouble caused, thanks alot for your help man.
it should be able to. i put the onlick attribute there and that should invoke the submittion of the form upon the clicking of the image. no idea whats happening.
do you have the from online, if so post the url and I will look at this problem.
you could try replacing the image with this:
<input type="image" src="magnifyingGlass.jpg" width="15" height="15" border="0" />i have never used it, but it might solve the problem.
it should be able to. i put the onlick attribute there and that should invoke the submittion of the form upon the clicking of the image. no idea whats happening.
do you have the from online, if so post the url and I will look at this problem.
hm, i do not have the online form cause it is running on my server.
well, this is my form codes.
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Corporate Phone Book</title>
<style type="text/css">
<!--
.style1 {
font-family: Verdana, Arial, Helvetica, sans-serif;
font-size: medium;
font-weight: bold;
}
.style7 {
font-family: Verdana, Arial, Helvetica, sans-serif;
font-size: x-small;
}
.style13 {font-family: Verdana, Arial, Helvetica, sans-serif; font-size: small;}
.style17 {font-family: Verdana, Arial, Helvetica, sans-serif; font-size: x-small; color: #0000FF; }
-->
</style></head>
<form method="get" action="Search.php">
<body>
<table width="119%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td colspan="2"> </td>
</tr>
<?php
//connecting to database
include ("config.php");
include ("opendb.php");
?>
<tr>
<td colspan="2"><span class="style1">Search function</span></td>
</tr>
<tr>
<td colspan="2"> </td>
</tr>
<tr>
<td height="69" colspan="2"><table width="894" height="82" border="0" cellpadding="0" cellspacing="1">
<tr>
<td width="406" rowspan="2"><table width="100%" height="57" border="0" cellpadding="0" cellspacing="1">
<tr>
<td width="402" height="42"><table width="100%" height="56" border="0" cellpadding="0" cellspacing="0" bgcolor="#CCCCCC">
<tr>
<td height="16" bgcolor="#CCCCCC" class="style13"><p>Search by first name ,last name and company name</p> </td>
</tr>
<tr>
<td bgcolor="#F0F0F0">
<div align="left">
<input name="txtSearch" type="text" id="txtSearch" size="40" />
<img src="magnifyingGlass.jpg" alt="Search" width="15" height="15" border="0" onclick="javascript<b></b>:this.form.submit()" />
</table></td>
</tr>Thanks alot once again.
why is there <b></b> tags in the onclick? that is the problem.
why is there <b></b> tags in the onclick? that is the problem.
haha, thanks dude, anyway the <b></b> doesn't affect anything.
changed it to
<input type="image" src="magnifyingGlass.jpg" width="15" height="15" border="0" alt="Search" onclick="javascript:this.form.submit()" />now it is working perfectly fine.
THANKS ALOT. :)
you can get rid of the onclick="javascript:this.form.submit()" , its not needed anymore.
you can get rid of the
onclick="javascript:this.form.submit()", its not needed anymore.
why is that so?
because the javascript was need on the image itself because its not an submit element.
<input type="image" src="image.jpg" />is the same as
<input type="submit" value="Submit" />because the javascript was need on the image itself because its not an submit element.
<input type="image" src="image.jpg" />is the same as
<input type="submit" value="Submit" />
Oh, i understand it now. Thanks alot for teaching me. :).
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