can not delete file from the FTP server,need help

Question

asifkamalzahid 0 Newbie Poster

15 Years Ago

n the following program i have the error
Warning: ftp_delete() [function.ftp-delete]: Access is denied. in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 89
could not delete wilbourn/ftptest/t.DOC

<?php 

//Move or Upload Folder Using PHP FTP Functions
function moveFolder($_server, $_user_name, $_user_pass, $local_dir, $remote_dir) {

echo"$_user_name <br/>";
echo"$_user_pass <br/>";
echo" directories are : <br/>";
echo"$local_dir<br/>";
echo"$remote_dir <br/>";



// set up basic connection
$_conn_id = ftp_connect($_server);

// login with username and password
$_login_result = ftp_login($_conn_id, $_user_name, $_user_pass);

// check connection
if ((!$_conn_id) || (!$_login_result)) {
$_error = "FTP connection has failed!";
$_error .= "Attempted to connect to $_server for user $_user_name";
$result = false;
} else {
$_error = "Connected to $_server, for user $_user_name";
}

$conn_id = $_conn_id;

$file = "t.DOC";
echo "Current directory: " . ftp_pwd($conn_id) . "\n";
echo "<br/>";


echo "<br/>";
if (ftp_chdir($conn_id, "$remote_dir")) {

    echo "Current directory is now After changes: " . ftp_pwd($conn_id) . "\n";
	
echo "<br/>";	
echo "<br/>";
echo "<br/>";	
	
	
	// try to delete $file
if (ftp_delete($conn_id, $file)) {
 echo "$file deleted successful\n";
} else {
 echo "could not delete $file\n";
}


}
 else { 
    echo "Couldn't change directory\n";
}

php

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Latest Post 15 Years Ago Latest Post by asifkamalzahid

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Rhyan

15 Years Ago

Check permissions for read/write/delete on the folder on the remote machine using the name / pass.

Rhyan

15 Years Ago

Hmmm.. I have had problem with file creation using php, so I had to change folder permissions to 777 and just then it worked.

I think also that you do not change the ftp_delete command, as it is protocol dependent, not OS dependent. In my opinion directory permissions are the key

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asifkamalzahid 0 Newbie Poster · Answer 1 · 2008-11-24T22:20:44+00:00

i have complete permission on all ftp server and all folder over there.
still telling me permission demied
i change the delete code

// try to delete $file
if (ftp_delete($conn_id, $file)) {
 echo "$file deleted successful\n";
} else {
 echo "could not delete $file\n";
}

to

unlink($file);

but still i have problom

asifkamalzahid 0 Newbie Poster · Answer 2 · 2008-11-24T22:42:59+00:00

yes bro you are right ,that was the problom it is ok now.
i am now going to upolad my folder to ftp, but it give the follwoing errors
successfully created /wilbourn/ftptest
Warning: readdir(): supplied argument is not a valid Directory resource in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 54

Warning: closedir(): supplied argument is not a valid Directory resource in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 65

Notice: Undefined variable: f in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 66

Notice: Undefined variable: result in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 83

the is following

<?php 

//Move or Upload Folder Using PHP FTP Functions
function moveFolder($_server, $_user_name, $_user_pass, $local_dir, $remote_dir) {

echo"$_user_name <br/>";
echo"$_user_pass <br/>";
echo" directories are : <br/>";
echo"$local_dir<br/>";
//echo"$remote_dir <br/>";



// set up basic connection
$_conn_id = ftp_connect($_server);

// login with username and password
$_login_result = ftp_login($_conn_id, $_user_name, $_user_pass);

// check connection
if ((!$_conn_id) || (!$_login_result)) {
$_error = "FTP connection has failed!";
$_error .= "Attempted to connect to $_server for user $_user_name";
$result = false;
} else {
$_error = "Connected to $_server, for user $_user_name";
}

$conn_id = $_conn_id;

//$file = 'vaf3.pdf';

echo "Current directory: " . ftp_pwd($conn_id) . "\n";
echo "<br/>";
	





echo "<br/>";
if (ftp_chdir($conn_id, "$remote_dir")) {

    echo "Current directory is now After changes: " . ftp_pwd($conn_id) . "\n";
	
	echo "<br/>";	echo "<br/>";	echo "<br/>";	
	
//unlink($file); 

@ftp_mkdir($conn_id, $remote_dir);
echo "successfully created $remote_dir\n";

$handle = opendir($local_dir);
while (($file = readdir($handle)) !== false) {
if (($file != '.') && ($file != '..')) {
if (is_dir($local_dir . $file)) {
//recursive call
moveFolder($conn_id, $local_dir . $file . '/', $remote_dir . $file . '/');
echo "successfully uploaded $file\n";
} else
$f[] = $file;
}     

}
closedir($handle);
if (count($f)) {
sort($f);
@ftp_chdir($conn_id, $remote_dir);
foreach ($f as $files) {
$from = @fopen("$local_dir$files", 'r+');
$moveFolder = ftp_fput($conn_id, $files, $from, FTP_ASCII);
// @ftp_fput($conn_id, $files, $from, FTP_BINARY);
// check upload status
if (!$moveFolder) {
$this->_error = "FTP upload has failed! From:" . $local_dir . " To: " . $remote_dir;
$result = false;
} else {
$this->_error = "Uploaded $local_dir to $remote_dir as $this->_server";
$result = true;
}
}
}
return $result;





	
// get the file list for 	
$buff = ftp_rawlist($conn_id, ".");
echo "<br/>";	
var_dump($buff);

}
 else { 
    echo "Couldn't change directory\n";
}


ftp_close($conn_id);

}

?>

Rhyan · Answer 3 · 2008-11-25T14:34:55+00:00

Well, honestly, I do not like while loops, so I would go with scandir() function in php that returns an array of all files. Then I will manipulate the array and upload file by file, rather than complete dir.
Also, I would like to use copy instead of move and once copy is successful, I would go with delete, calling another function.

But from the errors you get, I think the problem is here

$from = @fopen("$local_dir$files", 'r+');

I think this should look like

$from = @fopen("$local_dir/$files", 'r+');

asifkamalzahid 0 Newbie Poster · Answer 4 · 2008-11-25T16:09:10+00:00

ok i wil try on your idea then see what happened, i wil let you now later.
thanks

asifkamalzahid 0 Newbie Poster · Answer 5 · 2008-11-25T16:13:32+00:00

now i havw following errors
successfully created wilbourn/ftptest/
Warning: ftp_fput() expects parameter 3 to be resource, boolean given in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 79

Fatal error: Using $this when not in object context in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 83

asifkamalzahid 0 Newbie Poster · Answer 6 · 2008-11-25T16:50:04+00:00

i have noe error,
but the programe not understand my local directory
c:/ exampledirectory
it gives me the following errors

Warning: opendir(C:\1) [function.opendir]: failed to open dir: No such file or directory in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 59

Warning: readdir(): supplied argument is not a valid Directory resource in G:\WEBROOT\wilbourn\ftptest\uploadfunctionpage.php on line 60
i will show you the form i am using for data entry

Move or Upload Folder Using PHP FTP Functions<br />
</p>
<table width="373" border="1">
<tr>
<td width="184">server address </td>
<td width="173"><input type="text" id="server_name" name="server_name" /></td>
</tr>
<tr>
<td>user name </td>
<td><input type="text" name="user_name" id="user_name" /></td>
</tr>
<tr>
<td>user password</td>
<td><input type="text" id="user_password" name="user_password" /></td>
</tr>
<tr>
<td>local directory</td>
<td><input type="text" name="local_dir" id="local_dir" /></td>
</tr>
<tr>
<td>remote directory</td>
<td><input type="text" name="remote_dir" id="remote_dir" /></td>
</tr>
<tr>
<td> </td>
<td><input name="upload" type="submit" id="upload" /></td>
</tr>
</table>
<p>  </p>
</form>

</body>

do you think is there any syntax error or logical error.
waiting for reply

can not delete file from the FTP server,need help

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