hi,
hi i am php programmer. but i don't know how to use AJAX with php.
swi2
0
Newbie Poster
Recommended Answers
Jump to PostPHP AJAX is a brilliant tool
What were you intending to use it for?
Here is the base code:
javascript for head<script type="text/javascript"> function showData(str) { if (str.length==0) { document.getElementById("data").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else …
Jump to PostThe following example will demonstrate a poll where the result is shown without reloading.
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metalix
0
Posting Whiz in Training
PHP AJAX is a brilliant tool
What were you intending to use it for?
Here is the base code:
javascript for head
<script type="text/javascript">
function showData(str)
{
if (str.length==0)
{
document.getElementById("data").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("data").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","file.php?file="+str,true);
xmlhttp.send();
}
</script>and put this where you want the data to appear
<div id="data"></div>And your text field:
<input type="text" onkeyup="showData(this.value)" size="15" />this will work like googles smart search
--i think they call is SOAP
By getting the page 'file.php' setting variable q to the text search.
file.php
<?PHP
include (connection.php');
if($q){
mysql_select_db($database_connection, $connection);
$maxquery = "SELECT max(id) FROM table";
$max = mysql_query($maxquery, $connection) or die(mysql_error());
for($i=0;$i<=$max;$i++){
mysql_select_db($database_connection, $connection);
$query_Recordset1 = "SELECT DISTINCT FROM table WHERE column LIKE '$q' AND id='$i'";
$Recordset1 = mysql_query($query_Recordset1, $connection) or die(mysql_error());
$row_Recordset1 = mysql_fetch_assoc($Recordset1);
if($i){
if(!$results){
$results = $row_Recordset1['column'];
}
else{
$results .= ', '.$row_Recordset1['column'];
}
}
}
}
echo $results;
?>You obviously will need to reconstruct this
You can also use This to reload parts of a page by swapping the div with input from another page
Is this What you wanted to know?
Hope it helped :)
rajarajan2017
The following example will demonstrate a poll where the result is shown without reloading.
Danny.VBT
0
Newbie Poster
You'll have to be a little more specific, what exactly are looking to do with AJAX?
I suggest looking at JQuery, it's a popular javascript library that makes AJAX very simple.
(For instance, it handles all the browser compatibility code itself)
gaurang4
1
Newbie Poster
Hi, Agree 100% with Danny, use JQuery it would enhance development as well as ease of use.
Here is the very basic code to understand you may trick it for your requirements.
FORM.HTML
<html>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#btn1").click(function() {
$.ajax({
type: "POST",
url: "backend.php",
data: "name="+$("#txt1").val(),
success: function(msg){alert(msg);}
});
})
});
</script>
<input type="text" id="txt1"/>
<input type="button" id="btn1" value="Call Ajax"/>
</html>
BACKEND.PHP
<?php
echo $_POST["name"];
?>
Be sure to download the jquery.js file in the folder. you may get it from jquery.com
canterorist
0
Junior Poster in Training
hi! i agree with danny and guarang.I think jquery is popular today. you only need a file like jquery-1.4.2.min.js, it's free.
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