Anybody please help use the below table and tree structure and calculate left and right count.
My Table Creation Query:
CREATE TABLE testmlm.binary_tree (id INT( 11 ) NOT NULL AUTO_INCREMENT ,name VARCHAR( 150 ) NOT NULL ,left_id INT( 11 ) NULL ,right_id INT( 11 ) NULL ,level INT( 6 ) NULL ,
PRIMARY KEY ( id )
) ENGINE = InnoDB;
Field Type
------- ------
id int(11)
name varchar(150)
left_id int(11)
right_id int(11)
level int(6)
After inserting Values:
id name left_id right_id level
-- ---- ------- ---------- -----
1 abc 2 3 1
2 def 4 5 2
3 ghi 6 7 2
4 jkl 8 null 3
5 mno null 9 3
6 pqr null null 3
7 stu 10 null 3
8 vwx null null 4
9 yza null null 4
10 bcd null null 4
My Tree Structure
-------------------
id:1
/ \
id:2 id:3
/ \ / \
id:4 id:5 id:6 id:7
/
id:8 \ /
id:9 id:10
I want to create Customer List, and it will generate via MySQL queries like this for all above 10 Ids
For ID 1
Left Side Right Side
ID Name ID Name
2 def 3 ghi
4 jkl 6 pqr
5 mno 7 stu
8 vwx 10 bcd
9 yza
For ID 2
Left Side Right Side
ID Name ID Name
4 jkl 5 mno
8 vwx 9 yza
For ID 3
Left Side Right Side
ID Name ID Name
6 pqr 7 stu
10 bcd
For ID 4
Left Side Right Side
ID Name ID Name
8 vwx
For ID 5
Left Side Right Side
ID Name ID Name
9 yza
For ID 6
Left Side Right Side
ID Name ID Name
For ID 7
Left Side Right Side
ID Name ID Name
10 bcd
For ID 8
Left Side Right Side
ID Name ID Name
For ID 9
Left Side Right Side
ID Name ID Name
For ID 10
Left Side Right Side
ID Name ID Name
How its possible! Please help me...
