[mysql-numrows] Forum Topics

please i need help with my work.. write a program in c++ that accepts a real number with two decimal places and output the vallue in words.. [assume that no amount will exceed 999999999999.99

Hello everyone :) I have this lines of codes and i get : > Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in D:\xampp22\htdocs\folder\index.php on line 52 ( 19 in the code below ) <form method="POST" action="index.php"> CODE : <input type="text" placeholder="Type the code" name="searchfor" /> <input type="submit" …

Can anyone help me solve this problem, i tried everthing and googled all over everything, but still cant find solution, i hope somebody help me, ty, *sorry for my broken english $db=mysql_connect ("localhost", "root") or die ('I cannot connect to the database because: ' . mysql_error()); $mydb=mysql_select_db("database"); $sql="SELECT ID, FirstName, …

I know there are other post conserning this but they dont seem to help me. When I run the varaible `$results` through the function `Mysql_num_rows()` it returns as an error saying its not a valid result. Also same for the `mysql_fetch_array()`. function results(){ if ($_POST['search'] != "") { $search = …

Hello! This is my first post here, hehe. Seems to be a great site. Anyways, I'm quite new in PHP, but it's fun and I think I'm learning quite fast :) There's appeared a problem for me now though, and I can't see what the problem is...? I have made …

So im trying to make a password login and im getting errors. i got past my Unable to jump to row 0 error with this: **mysql_num_rows($result) >= 1** but now it wont jump to the row when the password is correct ether :/ here is the code; whats wrong with …

Hello! I want to create a script which mails emails to subscribers. I'm almost done, but I'd like it to say "Sent to # people". I've tried using: [CODE]<?php $dbc = mysqli_connect('localhost', 'username', 'password', 'database') or die('Error: Could not connect to database'); $query = mysql_query("SELECT * FROM table"); $number = …