#define max 50
struct code{int bits[max];int start;};typedef struct code code;
struct node{int freq;int father;int isleft;};typedef struct node node;

void insert(int,int);
int del(int);


main()
{
 	code cd,code1[max];
 	node node1[max*2-1];
 	int i,k,n,p,p1,p2,root,rootnodes;
 	char symb,alph[max];
 	for(i=0;i<max;i++)
 	alph[i]=' ';
 	rootnodes=0;
 	scanf("%d",&n);
 	for(i=0;i<n;i++)
 	{
	 					scanf("%s""%d",&symb,&node1[i].freq);
						insert(rootnodes,i);
						alph[i]=symb;
    }
    for(p=n;p<2*n-1;n++)
   { p1=del(rootnodes);
    p2=del(rootnodes);
    node1[p1].father=p;
    node1[p1].isleft=1;
    node1[p2].father=p;
    node1[p2].isleft=0;
    node1[p].freq=node1[p1].freq+node1[p2].freq;
    insert(rootnodes,p);
  }
root=del(rootnodes);
for(i=0;i<n;i++)
{	cd.start=max;
	p=i;
	while(p!=root)
       { 	cd.start-=1;
       		if(node1[p].isleft)
       		cd.bits[cd.start];
       		else
       		cd.bits[cd.start]=1;
       		p=node1[p].father;
       		
	   }
	   for(k=cd.start;k<max;k++)
	   {code1[i].bits[k]=cd.bits[k];
	   code1[i].start=cd.start;
	   }
	   for(i=0;i<n;i++)
	   {	
	   		printf("\n%c \t%d",alph[i],node1[i].freq);
	   		for(k=code1[i].start;k<max;k++)
	   		printf("%d",code1[i].bits[k]);
	   		printf("\n");
	   		
	   		
	   
	   
	   }
}

}

This is an incomplete code for implementing a Huffman Code using priority queue.
I have been given this code and i have to write the insert and delete functions
using priority queue.
However ,I am not able to understand somethigs like what is rootnodes here,what are exactly p1,p,p2?
Should i make priority queue with linked list or arrays?
Please help.

what are exactly p1,p,p2

This is an incomplete code

from where did you get this code?

from where did you get this code?

I have been given this code by my instructor

this is an awsum reply and answer that anyone can give... thnxxxxxxx

he gave incomplete code and asked -

what are exactly p1,p,p2?

i don't know - has he got the complete variant and does he understan't the idea upon the whole.....

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