hi....
Iam new to programming in C#,have just started programming.Can anyone tell me how to write code to convert numbers in to words...for istance if you put 1500 as input,the output should be "Fifteen Hundred.

Also i need a C# Code to check if an input string is an identifier or not.
Can anyone please help me out with these programs???
thanks,
unseenedges

Try the following code............

class NumberToWordsConvertor1
    {
        public  string NumberToText(int number) 
{ 
if (number == 0) return "Zero"; 

if (number == -2147483648) return "Minus Two Hundred and Fourteen Crore Seventy Four Lakh Eighty Three Thousand Six Hundred and Forty Eight"; 

int[] num = new int[4]; 
int first = 0; 
int u, h, t; 
System.Text.StringBuilder sb = new System.Text.StringBuilder(); 

if (number < 0) 
{ 
sb.Append("Minus "); 
number = -number; 
} 

string[] words0 = {"" ,"One ", "Two ", "Three ", "Four ", 
"Five " ,"Six ", "Seven ", "Eight ", "Nine "}; 

string[] words1 = {"Ten ", "Eleven ", "Twelve ", "Thirteen ", "Fourteen ", 
"Fifteen ","Sixteen ","Seventeen ","Eighteen ", "Nineteen "}; 

string[] words2 = {"Twenty ", "Thirty ", "Forty ", "Fifty ", "Sixty ", 
"Seventy ","Eighty ", "Ninety "}; 

string[] words3 = {"Thousand ", "Lakh ","Crore "}; 

num[0] = number % 1000; // units 
num[1] = number / 1000; 
num[2] = number / 100000; 
num[1] = num[1] - 100 * num[2]; // thousands 
num[3] = number / 10000000; // crores 
num[2] = num[2] - 100 * num[3]; // lakhs 

for(int i = 3; i > 0 ; i--) 
{ 
if (num[i] != 0) 
{ 
first = i; 
break; 
} 
} 


for(int i = first ; i >= 0 ; i--) 
{ 
if (num[i] == 0) continue; 

u = num[i] % 10; // ones 
t = num[i] / 10; 
h = num[i] / 100; // hundreds 
t = t - 10 * h; // tens 

if (h > 0) sb.Append(words0[h] + "Hundred "); 

if (u > 0 || t > 0) 
{ 
if (h > 0 || i == 0) sb.Append("and "); 

if (t == 0) 
sb.Append(words0[u]); 
else if (t == 1) 
sb.Append(words1[u]); 
else 
sb.Append(words2[t-2] + words0[u]); 
} 

if (i != 0) sb.Append(words3[i-1]); 

} 
return sb.ToString().TrimEnd(); 
} 

} // end class 

    }
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