How to Solve this..how preceedence works in this snippet

[muthu1802]

int i=5,j=6;
int k=i++ + i++ + ++i + i++;
int m=j++ + j++ + j++ - j++;
cout<<i;
cout<<m;
cout<<j;
cout<<k;

[daviddoria]

That should show you exactly how it works :) If you don't follow it, break it up into smaller statements: int m=n=j++ + j++; If you have specific questions let us know.

David

[jonsca]

AD's got it I think: http://www.daniweb.com/forums/post1395916.html#post1395916 (OP double posted this)

The problem is, the order of which the ++ and + will happen is implementation dependent.

[Fbody]

When you write equations like this, you are dealing with a whole lot of undefined behavior stemming from what are sometimes called "side effects". You should never write such a statement because the results are unpredictable at best.