Login functionality in C-language

your code is very good .
but if u provide one screenshot. it will be excellent
any way thank you

hi eswar.. thanks for your feedback..
do u want the screenshot of the console ?

i can't get. what is the id and pass. i am just a beginner.

what is the id and pass.

They're hard coded:

11user1 = Pwd1
12user2 = Pwd2
13user3 = Pwd3

i can't get. what is the id and pass.

They are on line 8 and 9:

char uid[25],pwd[25],s_uid[][25]={"11user1","12user2","13user3"};
char s_pwd[][25]={"Pwd1","Pwd2","Pwd3"},ch='a';/*dummy character in ch */

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <string.h>
main()
{
int i,counter=0,flag=0;
char uid[25],pwd[25],s_uid[][25]={"11user1","12user2","13user3"};
char s_pwd[][25]={"Pwd1","Pwd2","Pwd3"},ch='a';/*dummy character in ch */
 clrscr();
printf("\n Enter the user id : ");
scanf("%s",uid);
printf("\n Enter the password : ");
i=0;
while(1)
{
    ch=getch();
    if(ch==13)
    break;
    else if(ch==8)
    {       if(i!=0) /*this is for avoiding the ENTER instructions getting deleted */
        {
            printf("\b");  /*printing backspace to move cursor 1 pos back*/
            printf("%c",32);/*making the char invisible which is already on console*/
            printf("\b"); /*printing backspace to move cursor 1 pos back*/
            i--;
            pwd[i]='\0';
        }
        else
        continue;
    }
    else
    {
    putchar('*');/* char - '*' will be printed instead of the character */
    pwd[i]=ch;
    i++;
    }
}
pwd[i]='\0';
for(i=0;i<=2;i++)
{
    if((stricmp(uid,s_uid[i]))==0 && (strcmp(pwd,s_pwd[i]))==0)
    {
        flag=1;
        break;
    }
}
if(flag) printf(" \n \n \t \t USER AUTHENTICATED ");
else printf("\n \n \n\t TRESSPASSERS WILL BE SHOT AND SURVIVORS WILL BE SHOT AGAIN .. ha ha :)");
printf(" \n \n \tThanks for testing.. written by dileep basam :) ");
getch();
}