Akis2000

hi.. ok here is my problem i want to make a fuction that ask from the user which series he/she wants to use and the precision (number of digits, up to 10). If after 10000 iterations the series doesn't find the value of p, it should display an error message. …

hello, i have a double value=0; and i want before starting the calulation to round this value in the numbers that the user add, for example 2... any ideas??? I have despered...........

ok i need a quick help here...... here it's my problem It's approximate value of π is 3.141592653589793 Below are five di fferent series which can be used to approximate π: you can se the series here:: [URL="http://i44.tinypic.com/2ujtmxw.gif"]http://i44.tinypic.com/2ujtmxw.gif[/URL] ask which series he/she wants to use and the precision (number of …

ok i have 2 series of p... the user give which one was want... and then give the iterations that he/she want this is the series 4. P= sqrt(8*(1+ (1/9)+(1/25)+(1/49)+... )) 5. P= sqrt(24*((1/4)+(1/16)+(1/36)+(1/64)+...)) code:: first for series 4..... [code] int i; double: serieValue=0,pi=0; cout<<"Iterations"; cin>>i; for (long int n …

Problem Description My pi is an irrational number, i.e. it cannot be written as a fraction. It's approximate value of p is 3:141592653589793. Below are 5 di erent series which can be used to approximate p: 1. P= 4(1-(1/3)+(1/5)-(1/7)+(1/9)-... 2. P= sqrt(12(1- (1/4)+(1/9)-(1/16)+(1/25)-...)) 3. P= sqrt(6 (1+ (1/4)+(1/9)+(1/16)+(1/25)+...)) 4. P= …

hi.....here is my code::: [CODE]int main() { srand((unsigned)time(0)); int random_integer,num,len; cout << "Random numbers: "; cin >> num; cout<<"Lenght of each numbers: "; cin>>len; for (int i=0; i<num; i++) { cout<<endl; for(int j=0; j<len; j++) { random_integer = rand() %10 ; cout << random_integer; } } [/CODE] my question is... …

ok iam working on a password protection for my program but i have a problem..... if the user set wrong password the program do this Wrong password!! The program will be terminated in 5 seconds but i want sec, (which is my seconds) at every second - 1 5-4-3-2-1 without …