david_105

the menu works fine but the sub menu disappears when i select a menu, what am doing wrong thanks $query = "SELECT a.id, a.team1, a.team2, b.auction, b.bidder, b.tagged, b.willwin FROM " . $DBPrefix . "auctions a LEFT JOIN " . $DBPrefix . "bids b ON (b.auction = a.id) WHERE a.id …

hi am having a dependant drop menu issue . The menu part works fine but the submenu display data from all the table below are the codes plz what am i doing wrong //MENU TEAM $query = "SELECT u.id, u.nick, s.team_id, s.teams AS teams1, ss.team_id, ss.teams AS teams2, a.id, a.team1, …

hi how do i hide the (team_id) value in the below form <option value="' . $row['team_id'] . '' . $row['teams'] . '" ' . $selected . '>' . $row['teams'] . '</option> thanks

Am able to use this code to bind a.id = :auc_id in order to display certain result needed for menu code, but when i introduce it in the submenu i dont get any result below are the codes for menu and submenu' MENU works fine, display whats need to be …

how do i convert this <label for="category">Select Winner</label> <select name="willwin" id="willwin"> <?php if ($db->numrows() > 0){ while ($row = $db->fetch()) { ?> <option value=''></option> <option value="<?php echo $row["willwin"]; ?>"><?php echo $row["team1"]; ?></option> <option value="<?php echo $row["willlose"]; ?>"><?php echo $row["team2"]; ?></option> <?php } } ?> </select> <br/><br/> <label>Tag Bettor</label> <select name="sub_cat" …

i think this site is broken cause 1 spent half an hour trying to post code one of the reason why i left stack over flow