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friendly..
:)
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how to pass the value 'id_category' from this page list.php [code] <title>home</title> <!--for auto refresh--> <META HTTP-EQUIV=Refresh CONTENT="300; URL=http://localhost/recipe2/home.php"> <body> <div align="left"><img src="Cookie Banner edited.jpg" width="1100" height="200" /></div> <h2>My Account </h2> <p>chef today : <?php echo $_SESSION['myusername']; ?> | <a href="logout.php">Logout</a> </p> <p> </p> <p> </p> <?php include 'recipe2db.php'; $sql="SELECT id_category FROM … |
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after login, go to this page. client will click those button then view each recipe they click. list.php [code] <?php session_start(); if(!isset($_SESSION['myusername'])&&!isset($_SESSION['mypassword'])) { header('Location:401.php'); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <!--for auto refresh--> <META HTTP-EQUIV=Refresh CONTENT="300; URL=http://localhost/recipe2/home.php"> <title>home</title> </head> <body> <div align="left"><img src="Cookie … 
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update.php [code] <?php include 'recipe2db.php'; // get value of id that sent from address bar $id=$_GET['id']; // Retrieve data from database $sql="SELECT * FROM recipe WHERE id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array ($result); ?> <form name="form1" method="post" action="update_ac.php"> <table border="1" cellspacing="0" cellpadding="3"> <thead> <th>name</th> <th>ingredient</th> <th>how to cook</th> <th>category</th> </thead> <tr> <td> <input …
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i delete a row of data from this [code] ........ <a href="delete.php?id=<? echo $rows['id']; ?>">delete</a> [/code] delete.php [code] <html> <body> <?php include 'recipe2db.php'; // get value of id that sent from address bar $id=$_POST['id']; // Delete data in mysql from row that has this id $sql="delete from recipe where `id` … 
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add.php [code] <?php include 'recipe2db.php' ?> <div align="left"><img src="Cookie Banner edited.jpg" width="1100" height="200" /> <form name="form7" method="post" action="add_process.php"> </p> <p> </p> <table align="center" border="3" cellpadding="2" cellspacing="2"> <tr> <td>catagory :</td> <td> <?php include 'recipe2db.php'; $query="SELECT id_category, category_name FROM category"; $result = mysql_query ($query); echo "<select name=category value=''></option>"; // printing the list box …
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how to create an application for client and server through any port available using Red Hat Linux.. give some link to refer...
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we need to link this interface to database.. but i fail to connect this.. [code]<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <p><img src="header2.jpg" alt="header" width="800" height="100" /></p> <blockquote> <p align="left"><strong>Friends</strong>List</p> <p> <textarea … 
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