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php x 18
Member Avatar for praghna

Hi All, When i open my site in IE Browser i am getting as 400 image downloading in the status bar.How can i avoid this in my site.Can any one help me in solving this problem.Its urgent.My site is getting slow also due to this.

Member Avatar for colweb
0
70
Member Avatar for leviathan185

Hi, I am trying to write an upload script and everytime i try and upload a file it will give me an error. Warning: move_uploaded_file(/home/******/public_html/dw/uploads) [function.move-uploaded-file]: failed to open stream: Is a directory in /home/******/public_html/dw/upload2.php on line 3 I have checked that the folder is there as the error suggests …

Member Avatar for leviathan185
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170
Member Avatar for ersubhajit

I am getting this problem whenever I login from index.php to admin_area.php. I am giving the codes of the two files. Please help. Index.php [code=php]<?php session_start(); include("../lib/globals.php"); if(isset($_REQUEST['submit'])) { $u_name=$_REQUEST['username']; $pass=$_REQUEST['password']; $sql="select * from `user_table_master` where `user_name`='$u_name' and `password`='$pass'"; $result=mysql_query($sql); $row=mysql_fetch_array($result); $num_of_rows=mysql_num_rows($result); if($num_of_rows>0) { $_SESSION['logged_in']='y'; $_SESSION['user_type']=$row['user_type']; $_SESSION['user_formation']=$row['formation']; $_SESSION['user_name']=$row['user_name']; $_SESSION['name']=$row['name']; $_SESSION['user_id']=$row['user_id']; …

Member Avatar for guru12
0
151
Member Avatar for tulipputih

Hello, anybody can suggest me on how to do exact match in php ( for search purpose). From my reading I understand that we need to use " ". What is the correct syntax for this? Is preg-match important here. Thank you.

Member Avatar for praghna
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88
Member Avatar for NoID

Hello, i would like to know if its any chance of me being able to retrive data by typing ID, so for example if i type 100 and click on get, i want it to echo the "mobile" number. Can someone please help me with that Thank you

Member Avatar for NoID
0
113
Member Avatar for rahul8590

i designed a simple php form which accepts the data and then displays it, (well its supposed to ) but its kinda not displaying the values it should.. [code] <html> <head> <title> Simple feedback form </title> </head> <body> <form method = "post" action="send_simpleform.php"> <p><strong>Your name: </strong><br> <input type = "text" …

Member Avatar for telcontar
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150
Member Avatar for praghna

Hi all I am getting the following error with readfile: Warning: readfile() [function.readfile]: URL file-access is disabled in the server configuration in /home/u7/zzjynz5usy/ssss.com/html/news/news_index.php on line 144 can anyone help me in clearing this problem. I am using the readfile() function for generating rss feeds. my code is like this: readfile("http://www.webrss.com/get_mysite.php?mysiteId=10786");

Member Avatar for almostbob
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108
Member Avatar for dmotah

[icode]$sql_posts = 'select * from posts limit "'.$start.'", "'.$limit.'"';[/icode] im getting error with this line ?what could be the matter.. plz help

Member Avatar for praghna
0
39
Member Avatar for whiteyoh

Hi All, I am trying to echo the held text in the "Title" field where the id has a fixed value of 1, but i am getting the following error: supplied argument is not a valid MySQL result resource in C:\wamp\www\index.php on line 46 your help would be greatly appreciated. …

Member Avatar for whiteyoh
0
104
Member Avatar for modesto007

hi guys, im creating this contact form code, apparently its having error as below [Parse error: parse error, unexpected '"' in E:\wwwusr\vhosts\ceriategas-premium.com\httpdocs\test3\send_contact.php on line 6] ive checked the line 6, but i cnt find the errors... do help me please... [code] <?php if (isset($_POST['submit'])) { // Collect variables $subject="$name"; $message1="$coname"; …

Member Avatar for Josh Connerty
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169
Member Avatar for adindra

i have question why i cannot query or fetch array my database content from variabel id in my database table? everytime i have sql command in my php script : [code=php]$query = mysql_query("SELECT * FROM pengunjung WHERE id='$id'",$koneksi); while($baris=mysql_fetch_array($query))[/code] [B]variable id='$id' always cannot be take out from database.. because variable …

Member Avatar for adindra
0
131
Member Avatar for varun_1411