Funktion that returns all words not containing e

Hey, so i want to make a funktion that prints all the words from a list (words.txt) that doesn't contain the letter e.

I tried something like this:

def has_no_e2(word):
    fin = open('words.txt')
    for line in fin:
        word = line.strip()
        if letter in word:
            letter == ('e')
            print(word)

But i just can't make it work!
Please help.

[TrustyTony]

Are you sure that the function should print words, not return them. It seems strange that you overwrite the value of parameter at line 4 without using the original value. Also line 6 does nothing so you can remove that. words.txt does not look like list for me but more like file. Variable letter is also uninitialized at line 5.

[snippsat]

Here something you can look at.

>>> s = 'The quick brown fox jumps over the lazy dog'
>>> [i for i in s.split() if 'e' not in i]
['quick', 'brown', 'fox', 'jumps', 'lazy', 'dog']

Can break it up,code over is list comprehensions wish is much used in python.

>>> s = 'The quick brown fox jumps over the lazy dog'
>>> for item in s.split():
...     if 'e' not in item:
...         print item
...         
quick
brown
fox
jumps
lazy
dog

THX snippsat, I just got it working

def has_no_e2(word):
    line = fin.readline()
    for line in fin:
        word = line.strip()
        if 'e' not in line:
            print(word)

Its anoying, because i thought i already did this, but it didn't work at the time.
But at least now it does! :) Help much appreciated, some times i just need a push in the right direction!

[TrustyTony]

fin is undefined, but you are discarding first line at line 2 if it is previously set to open file. Original line 2 was more correct.

Still the word paramater does not do anything and line 4 is not needed if 6 would do print(line,) or print(line, end='') depending on your Python version.

[snippsat]

After your description this function dos what you want.
It`s more common to return out of function,than use print.
As you se it has no argument,because words comes from file.

def no_e():
    with open('fox.txt') as f:
        for item in f:
            words = item.split()
    return [word for word in words if 'e' not in word]

print no_e()

If we spilt it up it can look like this.
Now functions only dos 1 jobb an return out,this also show use of docstring.
This can be a good practise when code grow larger.

def read_file():
    '''Read a file and return words'''
    with open('fox.txt') as f:
        for item in f:
            words = item.split()
    return words

def no_e(words):
    '''Return all words,but not words that has "e" in it'''
    return [word for word in words if 'e' not in word]

if __name__ == '__main__':
    words = read_file()
    print no_e(words)
    help(read_file)

[JoshuaBurleson]

so you know, the function you created doesn't need the parameter word, but if you were abstracting the function, which is often considered better; you could make it something sort of like:

def no_e(word):
   noe=word.replace('e','')
   return noe

and then iterate through the words in the file and no_e them.

my interactive experiment with this:

>>> withh='electric slide'
>>> without=[]
>>> for word in withh.split():
	without.append(no_e(word))
>>> for word in without:
	print(word)

lctric
slid

[snippsat]

You miss the point pyguy62 .
It shall not replace "e" in words,but print all word that not contain 'e'.

prints all the words from a list (words.txt) that doesn't contain the letter e.

[JoshuaBurleson]

You miss the point pyguy62 .
It shall not replace "e" in words,but print all word that not contain 'e'.

Thank you snippsat, I don't know how I misread that; I will add that to my top ten list of reasons not to post after 1 am, sorry guys.

Hold for that "silly" mistake, my point to op was, and remains, that he could make a function abstract and use a parameter then, as opposed to assigning a specific file in the function; it seemed to me he was a little confused about how that worked from his initial post.