Posts
 
Reputation
Joined
Last Seen
0 Reputation Points
Unknown Quality Score

No one has voted on any posts yet. Votes from other community members are used to determine a member's reputation amongst their peers.

0 Endorsements
Ranked #31.8K
~5K People Reached
Favorite Forums
Favorite Tags

5 Posted Topics

Member Avatar for bitki_1407

You are trying to do math on a string value ... avg = txt_avg.Text // Line causing the error message // num1 = txt_num1.Text num2 = txt_num2.Text num3 = txt_num3.Text num4 = txt_num4.Text try something like num1 = val(txt_num1.Text) etc.. then avg = ( num1 + ... ) /4

Member Avatar for lordofhell
0
4K
Member Avatar for vb_learner

I don't use messenger programs, but if you post the code you have we can take a look and see where your problem lies.

Member Avatar for Edward-eh
0
404
Member Avatar for claysteven
Member Avatar for wednesday

label.text = listview.items(index).subitems(column).text The index is the line number, and colum is the item you want to retrieve ... both are 0 based.

Member Avatar for Yankie Dave
0
86
Member Avatar for anandarose

The code is below ... I have briefly commented it to give you an idea of what is going on, and left the keywords in lower case. I kept it very rough, there are many, better ways to do this, it is my intention you will look at the method …

Member Avatar for anandarose
0
253

The End.