- Strength to Increase Rep
- +0
- Strength to Decrease Rep
- -0
- Upvotes Received
- 1
- Posts with Upvotes
- 1
- Upvoting Members
- 1
- Downvotes Received
- 0
- Posts with Downvotes
- 0
- Downvoting Members
- 0
9 Posted Topics
plz let me know how to store the respond and take some logical actions upon it in visual STUDIO windows form application wht's the code for it; note that msdn suggest that it should be MessageBox::Show(" text here ", ,MessageBoxButtons::YesNo )==DialogResult::Yes but it's not working; DialogResult only has get() and … | |
i'm using visual c++ 2005 and in windows forms app how do i store a respond of a MSG box... the methods given in both MSDN new and the web mSDN doesn't seem to be working.if they worked in ur machine tell me the procedure i have to follow....plz help … | |
wht's Visual studio 2005 team edition sp1; wht's visual studio 2005 .net (RTM) wht's better among those two;and wht's the newest plz help me...i wanna buy one of these | |
this is my prob. i used goto as follows [code=c] int main() { l1: int x-9; goto l1; return 0; } [/code] this works as infinite unconditional loop is'nt it? this compiles well.which means there isnt an error. so can you explain how this variable declaration works when it get … | |
Re: first write a program to catch all the prime numbers in to an array in a given or a chosen range.... and compare the elements of prime numbers with the each element of the array u want... if one of ur array element is equal to a element of prime … | |
is there a library to manipulate the output or like ncurses in linux, in visual c++ in windows? or else tell me a way to move the cursor according to the coordinates x & y......like ncurses in linux. | |
Re: ok jus try out this code>>>>;;;;;; #include #inculde using namespace std; int main() {float a,b,c; cout<<"enter values for a,b,c\na: "; cin>>a; cout<<"b: "; cin>>b; cout<<"c: "; cin>>c; if (pow(b,2)>=4*a*c){ cout<<"the roots are"< | |
this is a program which will help you to find the roots of any given function.... and please note that i have made comments on the lines which compiler gives an error. actually it compiles really well. i think it is something wrong in the values which are assigned to … ![]() | |
Re: ok i got ur problem; i suppose u know integer division well; when u say n/2&&n/7 and when u enter a number for n between -7<n<7 u will get the correct message. but when u enter a number outside of tht range eg: n=15 n/2=7 n/7=2 therefore (n/2&&n/7) is true |
The End.