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Re: Compiler doesn't allow to convert pointer ( operator new always returns pointer ) to array type ( char* [13] ), so only way is to declare pointer: char** a=new char*[13]; a[0]="qwerty"; delete[] a; | |
Re: check keyword break; before case 3:, case 4:, case 5: | |
At runtime I obtain an instance of descendant of TObject (for example its name is TGoodForm). The definition of TGoodForm is unknown at compile time (I know that it is TGoodForm from TObject::ClassName()). [B]The question: how to create new instance of TGoodForm ?[/B] In another words, can I get address … |
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