Posts by lotrsimp12345

it needs to make sure numbers aren't duplicate and are ordered. maybe change my cout statements to arrays?
Thanks.
This is what program is supposed to do
input
Q 1,2,3-5,6-7
output
do problem 1,2,3,4,5,6,7 of Q.

#include <iostream>
#include <cstdlib>
#include <sstream>
#include <string>
using namespace std;

int main()
{


    cout <<"enter the problemset and number""\n";
    //problems represents name and numbers
    string problems;
    char quote;
    char num;
    short number, number2;
    
    //gather name
    if(cin.peek()=='"' || cin.peek() == '\'')
    {
        cin >>quote;
        getline(cin,problems,quote);
    }
    else
    {
        while (!isdigit(cin.peek()) && !isspace(cin.peek()))
        {
         //   (char)cin.peek();
            problems += cin.get();
        }
    }


    //gather problem numbers
    //cin >> num;
    
        cin>>number;
        cout<<"very beginning\n"<<number;
        
    while(cin.peek() != '\n')
    {
        
        if(cin.peek()==',')
        {
            cin.ignore();
            cin >> ws;
            if(isdigit(cin.peek()))
            {
                cin>>number;
                cout<<"from comma\n"<<number<<"\n";
            }
        }
       
        else if(cin.peek()=='-')
        {
            cin.ignore();
            cin >> ws;
            if(isdigit(cin.peek()))
            {
                cin>>number2;
                cout<<"the value of # is\n"<<number2;
                   
                for(short a=number+1; a<=number2; a++)
                {
                    cout<<"next do #"<<a;
               
                }
            }
        }
        
    }
    
    //check for dulplicate and put in order
        
    // print them all out

    return 0;
}

so insert something like this in my for loop?

if(int index=find_first_of(syll)
    {
         substring(0,index+1);
    }

#include<iostream>

using namespace std;
int main()
{
string passage;
int space=0;
int sentence=0;
int word=0;
int character;
int index;
string delimeter=".:;!?";
string syllable;
string syll="aeiou";
cout<<"enter the passage to find out readability index";
getline(cin,passage);
    for (int  i = 0; i < passage.length(); i++)
    {
        //number of words
        if (isspace(passage[i]) )
        {        
            space++;
        }
        word=space+1;
        //number of sentences
        if(character=(passage.find_first_of(delimeter)))
        {
            passage.erase(0,character+1);
            sentence++;
        }
        //number of syllables
        
    //cin.get();
    }
    syllable=passage.c_str();
    cout<<"the syllable is"<<syllable;
    
    return 0;
}

i have created a C string of my variables and guessing i need some king of loop to check each character after it gets it?

it seems to work thank you.

oh okay i will give that a try.

so i would need to make a method to find the issentence?

how do i find out # of sentences if they contain a :, :, ! or ?

i am trying to find out the # of sentences they enter in a text. here's a link to the assignment.
http://home.earthlink.net/~craie/122/projects/diffrate.html

#include<iostream>

using namespace std;
int main()
{
string passage;
int space=0;
int sentence=0;
int word=0;
int character;
cout<<"enter the passage to find out readability index";
getline(cin,passage);
    for (int  i = 0; i < passage.length(); i++)
    {
        //number of words
        if (isspace(passage[i]) )
        {        
            space++;
        }
        word=space+1;
        //number of sentences
        if(character[i]==(passage.find('.')))
        {
            passage.erase(0,character+1);
            sentence++;
        }
        
    }
    cout<<"the sentence is"<<sentence;
    cin.get();
    return 0;
}

it still gives me error. invalid type int[int]

why doesn't the or operator work here? when i try to include semicolon.

can someone check if this makes sense to find # of sentences. i think it does.

#include<iostream>

using namespace std;
int main()
{
string passage;
int space=0;
int sentence=0;
int word=0;
int character;
cout<<"enter the passage to find out readability index";
getline(cin,passage);
    for (int  i = 0; i < passage.length(); i++)
    {
        //number of words
        if (isspace(passage[i]) )
        {
            space++;
        }
        word=space+1;
        //number of sentences
        if(character=(passage.find('.')))
        {
            passage.substr(0,character);
            passage.erase(0,character+1);
            sentence++;
            cout<<"should print out multiple";
        }
        
    }
    cout<<"the sentence is"<<sentence;
    //cin.get();
    return 0;
}

so i find the period or whatever the sentence ends in. Then I create a substring from that and delete the part which contains the end character. Then i keep count of it.

so my original problem still remains for anything which is 2 char or above for a number.

thank you for your help. It works.

now it says comparison between unsigned and signed integer expressions
so do i say one is unsigned type?

gives me weird error of includes atleast one deprecated or antiquated header.
And it doesn't seem to capture # of spaces.

#include<iostream.h>

using namespace std;
int main()
{
string passage;
int space;
cout<<"enter the passage to find out readability index";
cin>>passage;
getline(cin,passage);
    for (int  i = 0; i < passage.length(); i++)
    {
        if (isspace(passage[i]) )
        {
            space++;
        }
        cout<<"the number of spaces is"<<space;
    }
}

the loop doesn't quite work for 2 digit numbers.

don't believe so here's a link to problem.
http://home.earthlink.net/~craie/122/labs/seqlist.html
i need comma because i need to check for duplicates and make it into an ordered list.

now how would i get a comma to appear between each of them. my updated code is

#include <iostream>
#include <cstdlib>
#include <sstream>
#include <string>
using namespace std;

int main()
{


    cout <<"enter the problemset and number""\n";
    //problems represents name and numbers
    string problems;
    char quote;
    char num;
    string number;
    
    //gather name
    if(cin.peek()=='"' || cin.peek() == '\'')
    {
        cin >>quote;
        getline(cin,problems,quote);
    }
    else
    {
        while (!isdigit(cin.peek()) && !isspace(cin.peek()))
        {
            (char)cin.peek();
            problems += cin.get();
        }
    }


    //gather problem numbers
    //cin >> num;
    char lastdigit=0;
    while(num != '\n'){
        
        cin.get(num);
        cout<<"very beginning\n"<<num;
        
        if(num==',')
        {
            if(isdigit(cin.peek()))
            {
                cin.get(num);
                cout<<"from comma\n"<<number<<"\n";
            }
        }
       
        else if(num=='-')
        {
            
            if(isdigit(cin.peek()))
            {
                cin.get(num);
                cout<<"the value of # is\n"<<num;
                   
                for(char a=lastdigit+1; a<num; a++)
                {
                    number = number + a;
                    lastdigit=num;                                                      
                }
            }
        }
        number=number+num;
        lastdigit=num;
    }
    
    cout<<"the final number is"<<number<<"\n"; 
        
    // print them all out

    return 0;
}

thank you very much.

i need the integers though because i want my final value to be 1,2,3,4,5 in this case. and it doens't like atoi.

basically i am trying to create a readibility index so i need the number of vowels, words and sentences. I am stuck on how to approach this.

i can't figure out where the lastdigit which represenst beginning of the index which has a - would go to.
help would be appreciated.

so input would be
Q1,2,3-5
output would be
do problems 1,2,3,4,5 of Q

#include <iostream>
#include <cstdlib>
#include <sstream>
#include <string>
using namespace std;

int main()
{


    cout <<"enter the problemset and number""\n";
    //problems represents name and numbers
    string problems;
    char quote;
    char num;
    string number;
    
    //gather name
    if(cin.peek()=='"' || cin.peek() == '\'')
    {
        cin >>quote;
        getline(cin,problems,quote);
    }
    else
    {
        while (!isdigit(cin.peek()) && !isspace(cin.peek()))
        {
            (char)cin.peek();
            problems += cin.get();
        }
    }


    //gather problem numbers
    //cin >> num;
    int lastdigit=0;
    while(num != '\n'){
        
        cin.get(num);
        cout<<"very beginning\n"<<num;
        
        if(num==',')
        {
            if(isdigit(cin.peek()))
            {
                cin.get(num);
                cout<<"from comma\n"<<number<<"\n";
            }
        }
       
        else if(num=='-')
        {
            
            if(isdigit(cin.peek()))
            {
                cin.get(num);
                cout<<"the value of # is\n"<<num;
                for(int a=lastdigit; a<num; a++)
                {
                }
            }
        }
        number=number+num;
    }
    
    cout<<"the final number is"<<number<<"\n"; 
        
    // print them all out

    return 0;
}

#include <iostream>

using namespace std;

int main()
{
    cout<<"enter a passage into input to find out how difficult it is to read\n";
    string passage;
    cin>>passage;
    char letter;
    int space=0;
    while(letter!='\n')
    {
        cin.get(letter);
        while(letter=" ");
        //while(isspace(cin.peek())&&letter=='\n')
        {
            cin.get(letter);
            cout<<"the letter is"<<letter;
            space++;
        }
    }
    cout<< space;
    return 0;
}

so it prints out but is an infinite loop, need to check if they do enter '\n' character how to do that?

here's my code, don't see why it doesn't print out

#include <iostream>

using namespace std;

int main()
{
    cout<<"enter a passage into input to find out how difficult it is to read\n";
    string passage;
    cin>>passage;
    char letter;
    int space=0;
    while(letter!='\n')
    {
        if(isspace(cin.peek())&&letter=='\n')
        {
            cout<<"from space";
            space=space++;
        }
    }
    cout<< space;
    return 0;
}

i got it to work. had to change some properties of how is built.

yea it compiles in one file. But i need library.

undefined reference to 'test::alternate(int)'

nope it isn't solved.

thanks for help.

that still doesn't solve my original issue.

modified my implementation

#include <iostream>
#include <cctype>
#include <cstdlib>
using namespace std;
#include "libro.h"

int test::alternate(int width)
{
    //for odd, 3 char-ellipsis
    if(width%2==1)
    {
        if(width)
        {
         keep=width-3;
        }
    }
    //for even, 4 char-ellipsis
    else if(width%2==0)
    {
        if(width)
        {
        keep=width-4;
        }
    }

    keep_per_end=keep/2;
    return keep_per_end;
}

in my main it doesn't like ab.alternate(length);

my problem is that it doesn't return keep_per_end, my program doesn't compile

//main

#include <iostream>
#include <cstdlib>
using namespace std;
#include "libro.h"
int main()
{
    test ab;
    cout<<"enter width limit";
    int length;
    cin>>length;
    ab.alternate(length);
}

http://home.earthlink.net/~craie/122/labs/dot.dot.html

the function is supposed to find out the number of characters at each end of a string it is supposed to store. and insert ... if odd and .... if even

changed my code on top.

ab is not right? in my main?

//main

#include <iostream>
#include <cstdlib>
using namespace std;
#include "libro.h"
int main()
{
    test ab;
    cout<<"enter width limit";
    int length;
    cin>>length;
    ab.alternate(length);
}

//implementation

#include <iostream>
#include <cctype>
#include <cstdlib>
using namespace std;
#include "libro.h"

int test::alternate(int width)
{
    //for odd, 3 char-ellipsis
    if(width%2==1)
    {
         keep=width-3;
    }
    //for even, 4 char-ellipsis
    else if(width%2==0)
    {
        keep=width-4;
    }

    return keep_per_end=keep/2;
}

//interface

#ifndef LIBRO_H_INCLUDED
#define LIBRO_H_INCLUDED
#include <iostream>
using namespace std;

class test
{
    public:
    //check if even or odd 
    int alternate(int width);
    int keep_per_end;
    int keep;
};
#endif // LIBRO_H_INCLUDED

thanks for help but i haven't learnt about pointers so i need another way of doing the problem. Its okay though i will just ask him tom.

yea basically he only wants me to use c-string and string. Here's a link to what he wants me to do. Maybe i am supposed to read the sentence as a string.
http://home.earthlink.net/~craie/122/labs/strfind.html

most recent code

//main

#include <iostream>
#include <cstdlib>
using namespace std;
#include "strextra.h"

int main()
{
    Search a;
    cout<<"enter max number of characters in the sentence";
    int number;
    cin>>number;
    cout<<"enter a sentence";
    string mycstring;
    cin>>mycstring;
    cout<<"my string is\n"<<mycstring<<"\n";
    cout<<"enter the character you are trying to find in the string above\n";
    char alpha;
    char lett[2];
    cin>>alpha;
    lett[0]=alpha;
    lett[1]='\0';
    cout<<lett[0]<<lett[1];
    a.find(mycstring, lett[0]);
}

//implementation

#include <iostream>
#include <cstdlib>
#include <cstring>
using namespace std;
#include "strextra.h"

int search::find(string mystring,char letter[0])
{
    return strchr(mystring,letter);
}

//interface

#ifndef STREXTRA_H_INCLUDED
#define STREXTRA_H_INCLUDED
#include <iostream>

using namespace std;

class Search
{
    public:
    int find(string mystring,char letter[0]);
    int find(char mystring,string word);

};

#endif // STREXTRA_H_INCLUDED

so i am just going to have them read in a string for the input of the sentence and a c-string for the char they are trying to find.

see i have a teacher but no lecture so basically i have to teach myself.

i am really confused now.

oh k now it makes sense. And with the methods a.find i can't pass in a variable?