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 | >how do u insert nth square into a complicated formulea? like p={d[I(1+I)*n-th power]}/{(1+I)*n-th power-1} izzit [static int power(doubleb,doublen){ if (n==0) return 1; else{ int p=power (b, n/2); if (n%2==0) return p*p; else returnp*p*b; }] And this statement [cal.addActionListener(this);] the same as [System.out.println("cal");]? |
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