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Member Avatar for himit

U have to use recursion for this task. Give me an instance and i'll solve that problem.... :)

Member Avatar for Balakumar_1
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Member Avatar for liveland

Hi Liveland, In this XSLT , the value of sort param is blank or null. In used <xsl:choose> u dont have any <xsl:when> which can test for null value of $sort. So it is going to <xsl:otherwise>. # <xsl:param name="sort">DATE</xsl:param> use this line in place of urs, it'll enter into …

Member Avatar for solutiongiver
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Member Avatar for pankajagar2002

Use following code:- <bb> <xsl:for-each select="//x"> <xsl:if test="position() &lt;6"> <xsl:copy-of select="."/> </xsl:if> </xsl:for-each> </bb> <cc> <xsl:for-each select="//x"> <xsl:if test="position() &gt;5"> <xsl:copy-of select="."/> </xsl:if> </xsl:for-each> </cc>

Member Avatar for varun0703
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Member Avatar for Bash23

Hi, Dont wrry!!! i'll solve that but i need XML data ??? would u like to paste ur XML content here so that i might write correct x-Path?????

Member Avatar for varun0703
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132
Member Avatar for k_manimuthu

[QUOTE=k_manimuthu;1116055]Hi All, I am trying to get the maximum no of column in a table through XSLT code. Below i had placed the sample table format. Here column tagged as 'th' and 'td'. Some of the column having 'colspan' attribute. I am struggling how to add colspan value in a …

Member Avatar for varun0703
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836
Member Avatar for prashantc13

Firstly, this XML is not well-formed. Use any root element. Suppose u added <doc>at the beginning and </doc> at last then..... use . <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/"> <xsl:for-each select=".//*[@text='catalog']"> <xsl:element name="{@text}"> <xsl:for-each select="./*"> <xsl:element name="{@text}"> <xsl:for-each select="./*"> <xsl:element name="{@text}"><xsl:value-of select="./*/@text"/></xsl:element> </xsl:for-each> </xsl:element> </xsl:for-each> </xsl:element> </xsl:for-each> </xsl:template> </xsl:stylesheet> u'll surely …

Member Avatar for varun0703
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The End.