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c x 29
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Member Avatar for Muhammadlodhi

Hi I am making a banking system in c++ but getting a problem I am not sharp in programmin if you can help then thanks [CODE]//*************************************************************** // HEADER FILE USED IN PROJECT //**************************************************************** #include<iostream> #include<conio.h> #include<stdio.h> #include<process.h> #include<fstream> #include<ctype.h> //*************************************************************** // CLASS USED IN PROJECT //**************************************************************** using namespace std; class …

Member Avatar for Salem
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Member Avatar for Muhammadlodhi

Hi i made a program for conversion decimal to binary number ... but i need to convert the big dottef number into dotted binary like this For example 10.10.0.13 is <00001010.00001010.00000000.00001101> 8-bit of every integer .. This is making me confuse how to make it ? my conversion code is …

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Member Avatar for Muhammadlodhi

Hi . I am coding the following program i will give the string my self and one is already given. given string = {a,b,c,d,3,f,g,h,i,6,j,k,l,m,9,n,o,p,q,2,r,s,t,u,v,w,x,y,z }, you are required to process an input string possibly less than 80 characters long, and an input +ive integer to encrypt the message: for example: …

Member Avatar for Muhammadlodhi
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Member Avatar for Muhammadlodhi

Hi .. i want to print this pattern of number using loops . if input is 5 then output should be ... 155555 224444 333333 444422 555551 i have solved 1 22 333 4444 55555 but another reflection is not coming in my mind ... and making me confuse need …

Member Avatar for Muhammadlodhi
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105
Member Avatar for Muhammadlodhi

[CODE]int main(){ char i,input[30],close,open; for(i=0;i<='.';i++){ printf("enter equation"); scanf("%c",input[i]); if(input[i]=='(') input++; input[i]=open; else if(input[i]==')') input[i]--; input[i]=close; else if(open[i]==close[i]) { printf("paranthesis are balance"); } else printf("paranthesis are not balance"); } getch(); return 0; }[/CODE]

Member Avatar for jephthah
-2
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Member Avatar for Muhammadlodhi

i want to write this program without lib and string files make changes in it and tell me the program thanks code is below[CODE]#include<stdio.h> #include<conio.h> #include<stdlib.h> #include<string.h> struct Node; typedef struct Node * PtrToNode; struct Node { char element; PtrToNode Next; }; PtrToNode MakeEmpty(PtrToNode L) { L= new(Node); L->Next=NULL; return …

Member Avatar for Muhammadlodhi
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Member Avatar for Muhammadlodhi

This is begining. BALANCE PARANTHESIS and show the result of ((9-4)/(44*34)) etc ??? what to do? int main() { char arr[30]; for(int i=0;i<30;i++){ if(c=='(') c++; else if(d==')') d++;} if(c==d) printf("parenthesis are balance"); else printf("are not balance"); } further cant understand.

Member Avatar for Adak
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Member Avatar for Muhammadlodhi

[I][B][B][/B][/B][/I] i want to put the answer like user enter any odd number then out put will be like this one if 3 *** * * *** the even rows shows only 1st and last stars LIKE 5 ***** * * ***** * * ***** [CODE] int main(){ int num,i,j,k,l; …

Member Avatar for Muhammadlodhi
0
252
Member Avatar for Muhammadlodhi

HI i made this program for odd inputs if press 5 then ***** * * ***** * * ***** but not showing the correct answer. write a right code if u can plz thanks alott. [CODE] #include <stdio.h> int main() { int num, i; printf("press any odd num"); scanf("%d", &num); …

Member Avatar for jephthah
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Member Avatar for Muhammadlodhi

I need your help AT ONCE plz IN C CODE ONLY i have a program to make an array of length 30 and NOW write equation like this ((3+4)-(24/5)) .... the paranthesis must be balance and the output of the operation must be shown IF paranthesis are balanced. HELP ME …

Member Avatar for Nick Evan
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Member Avatar for Muhammadlodhi

Hey guys and girl i need your help in program only in C CODE user press only odd numbers then the following result has been shown like if 3 then *** * * *** if 5 then ***** * * ***** * * ***** PLZ HELP ME >>>> Thanks

Member Avatar for Salem
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