8 Solved Topics
Remove Filter  | Hi, I have overloaded assignment operator like below and it worked perfectly fine. [CODE]void Test::operator = (Test& obj) { this->a = obj.a; this->b = obj.b; } [/CODE] But when I googled more about this, I could see all of the examples used a different prototype like this [CODE]Test& Test::operator = … |
| | Hi all, Sorry if this is a stupid question. Assume I have a code like this. [CODE] char *temp = "poiuytrewq"; std::cout<<*temp<<std::endl; //should print p function(temp); std::cout<<*temp<<std::endl; //should print i [/CODE] Basically my function() in the above snippet increments the pointer twice so that temp point to 'i' now. I … |
| | Hi all, I'm trying to get an octal number from console and store it in an int variable using scanf. Here is my code. [CODE] int n; scanf("%i", &n); printf("\nEntered number in dec = %d", n); printf("\nEntered number in hex = %x", n); printf("\nEntered number in oct = %o", n); … |
| | Hi friends, I was understanding the concept of friend functions. I read in my book that there are two possible ways of "making friendship":cool: 1. Make a class a friend. 2. Make the method in a class a friend. I am able to write a code for the first point. …  |
| | Hi friends, One of my class member function is supposed to return an array of integers. Here's the function. [CODE]int* MyClass::getallVars() { int* a = new int; int b[] = { GetparentVar1(), GetparentVar2(), GetchildVar1(), GetchildVar2(), }; a=b; return a; }[/CODE] Is there anyway I can do this without the use … |
| | Hi friends, I know this is such a freak code, but out of curiosity I did it to see memory usage increase using new operator. [CODE]int main() { char* a; for (;;) { //cout<<&a<<endl; a = new char[10]; } }[/CODE] As you see line7 is commented. When i run this … |
| | I'm trying something like this [CODE]void receiver (char* x) { cout<<x<<endl; //prints "a" cout<<*x<<endl; //prints "a" cout<<&x<<endl; //prints address of x } int main() { char p = 'a'; cout<<p<<endl; //prints "a" cout<<&p<<endl; //prints "a" receiver(&p); } [/CODE] In the main function for both p and &p, it is printing … |
| | In C++ I'm able to do something like this [CODE](some_condition)? function1():function2();[/CODE] When i tried the same thing in Java it's not possible. It wants some variable to hold the result even though the return type of function1 and function2 are void. Is there any other way to do it other … |
The End.