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c++ x 2

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rational operator+(rational d)//where num and den are numerator and denominater { int k,n; rational f; k=den*d.den; for(int i=1;i<=k;i++) { if(i%den==0 && i%d.den==0) { n=i; break; } else { n=k; } } f.num=(n/den)*num+(n/d.den)*d.num; f.den=n; return (f); } I think I helped

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The End.