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16 Posted Topics
Re: The main difference between while and for loop is "for" can execute without condition but when we execute while function the condition is mandotary........ Ex: [CODE]void main() { int i; for(;;) //Means an infinate loop { if(i<10) break; i++; } printf(" %d ",i); }[/CODE] -----No error executes succesfully---- Ex: [CODE]void … | |
Re: [CODE] #include<stdio.h> #include<conio.h> #include<stdlib.h> int main() { int a,i; printf("\n Enter a number : "); scanf("%d",&a); for(i=2; i<=a/2; i++) { if(a%i==0) { printf("\n Not a prime number"); getch(); exit(0); } } int a,i; printf("\n Enter a number : "); scanf("%d",&a); for(i=2; i<=a/2; i++) { if(a%i==0) { printf("\n Not a prime … | |
Re: "The hidden treasure of c" by Rajiv Dhaneskar | |
Re: [CODE] #include<stdio.h> #include<conio.h> int main() { int n,i,rev=0,num; printf("\n Enter a number : "); scanf("%d",&n); num=n; while(n) { rev=rev*10+n%10; n/=10; } if(num==rev) printf("\n Is Armstrong"); else printf("\n Not an Armstrong"); } [/CODE] | |
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Re: In line number 17 and 21 %c is replaced as %s...... | |
Re: For this problem you refer the book let us c...... I think the chapter number is 8 or 9 is about Keyboard | |
Re: In line number 31 replace the code as while(ch!='\n'); | |
Re: First of all you know about the fibonacci series........ After that try to implement the code for that...... | |
Re: In line number : 31 just modify your code as while(ch!='\n'); | |
Re: [CODE]#include<stdio.h> #include<conio.h> int main() { int a[10]; int i; int esum=0,osum=0; // One for even sum and one for odd sum printf("\n Enter 10 numbers : "); for(i=0;i<10;i++) scanf("%d",&a[i]); for(i=0;i<10;i++) { if(a[i]%2==0) esum=esum+a[i]; else osum=osum+a[i]; } printf("\n Even numbers sum is : %d",esum); printf("\n Odd numbers sum is : %d\n",osum); … | |
Re: If ur the beginner of programming language the come to anantapur and join to madhavi infotech software training........ It's very good and useful to u....... | |
Re: the parameters taking of printf function is from right to left..... So in the given problem the function executes as follows.... b=1; printf("\n %d %d %d",b=15, b>9, b<9); So first it executes the condition b<9 but here b=1 next it executes the condition b>9. Here also b=1 and the last … | |
Re: using the functions textbackground(int) and setbkcolor(int) .. textbackground(int) prototype is in the header file conio.h and setbkcolor(int) prototype is in the header file graphics.h and | |
Re: [CODE]#include<stdio.h> #include<conio.h> #include<string.h> #include<ctype.h> #include<stdlib.h> int main() { char org[50],r[50],m[50],a; int i,j,c=0,length=0,h=0,g=0,z; char token [3] [20] = { "void", "main", "int"}; printf("\nenter a line:"); gets(org); for(i=0; org[i]!='\0'; i++) length++; while(g!=length) { for(g; g<length; g++) { if(org[g]==' ' || org[g]=='\n' || org[g]=='\t') { g++; break; } m[c++]=org[g]; } m[c]='\0'; for(h=0; h<3; … | |
Re: if u knw about the concept of buffer then easily u can this problem urself........ |
The End.