# Calculate the daycode of a date

OK I know the DateTime structure is very good at doing this.
But if you ever wanted to design your own calendar, or just wanted to know how things are possibly done, this could be a handy function. Enjoy.

``````public int dateDaycode(int year, int month, int day)
{
//Using Zeller's formula
int d1, d2, d3, d4, code;
if (month == 1)
{
month = 13; year--;
}
if (month == 2)
{
month = 14; year--;
}
d1 = year / 4;
d2 = year / 100;
d3 = year / 400;
d4 = day + 2 * month + 3 * (month + 1) / 5 + year;
code = (d4 + d1 - d2 + d3 + 1) % 7;
return code;
// code will be sun=0,mon=1,tue=2,wen=3,thu=4,fri=5,sat=6
}``````
xrjf 213

Long time ago, by means of Bussiness Basic, I had this problem as "homework". It did was a headache and there was no Wikipedia nor Internet, just some colleagues comments that really did their best. Allow me to contribute with the following code:

``````        static void Main(string[] args)
{
System.Globalization.CultureInfo ci =
new System.Globalization.CultureInfo("en-US");
ci;
Int32 initYear = 1990;
Int32 curYear = initYear;
DateTime dt = new DateTime(curYear, 1, 1);
DateTime dtStop = DateTime.Today;
Int32 nErr1, nErr2, nDates;
Int32 code0, code1, code2;
do
{
Console.Write(dt.ToString("yyyy/MM/dd"));
code0 = (Int32)dt.DayOfWeek;
code1 = dateDaycode(dt.Year, dt.Month, dt.Day);
if (code0 != code1)
nErr1++;
code2 = dateDaycodeWiki(dt.Year, dt.Month, dt.Day);
if (code0 != code2)
nErr2++;
Console.WriteLine();
if (dt.Year != curYear)
{
curYear++;
dt = new DateTime(curYear, 1, 1);
}
nDates++;
} while (dt <= dtStop);
if (nErr1 != 0)
Console.WriteLine(nErr1.ToString() + " code 1 errors found ");
if (nErr2 != 0)
Console.WriteLine(nErr2.ToString() + " code 2 errors found ");
Console.WriteLine(nDates.ToString() + " total days between dates 01/01/" +
initYear.ToString() + " and " + dtStop.ToShortDateString());
Console.WriteLine("Press Enter to exit");

}
public int dateDaycode(int year, int month, int day)
{
//Using Zeller's formula
int d1, d2, d3, d4, code;
if (month == 1)
{
month = 13; year--;
}
if (month == 2)
{
month = 14; year--;
}
d1 = year / 4;
d2 = year / 100;
d3 = year / 400;
d4 = day + 2 * month + 3 * (month + 1) / 5 + year;
code = (d4 + d1 - d2 + d3 + 1) % 7;
return code;
// code will be sun=0,mon=1,tue=2,wen=3,thu=4,fri=5,sat=6
}
public int dateDaycodeWiki(int year, int month, int day)
{
/* see http://es.wikipedia.org/wiki/Congruencia_de_Zeller
or http://en.wikipedia.org/wiki/Zeller%27s_congruence */

Single h;
Int32 code;
if (month == 1)
{
month = 13; year--;
}
if (month == 2)
{
month = 14; year--;
}
h = (day + (month + 1) * 13 / 5 + year + year / 4 + 6 * (year / 100) + year / 400) % 7;
// h: 0=sat, 1=sun, 2=mon, ...., 6=friday
code = (int) (Math.Floor(h) + 6) % 7;
// code will be sun=0,mon=1,tue=2,wen=3,thu=4,fri=5,sat=6
}
``````
commented: Allow me to upvote, albeit a bit late I guess. :) +15
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