hey all,

i'm a newbie to C++ programming and i'm having some difficulties implementing this singly linked list.

what it has to do is accept:
nickname
email address
number of kills

and store them in a node of the linked list in order according to number of kills.

here's what i've got, it seems to accept the number of kills, but i run into problems when i try to accept anything else.

#include<iostream.h>
#include<process.h>
class Soldier
{
public :
    Soldier * Sort(Soldier *);
	void Show(Soldier *);

private:	
    Soldier * ptrNext;
	int kills;
    int sorter;
    char nickname[25];
    
};
Soldier * Soldier::Sort(Soldier* temp)
{
	Soldier * ptrNew;
	Soldier* dummy1;
	ptrNew = new Soldier;
    cout << "\nEnter soldiers nickname\n";
    cin >> nickname;
	cout << "\nEnter number of kills for the month:\n";
	cin >> sorter;
    dummy1 = temp;
	if (temp == NULL || dummy1->kills > sorter)
	{	
		ptrNew->kills = sorter;
		ptrNew->ptrNext=temp;
		temp=ptrNew;		
		return temp;
	}
	else
	{
		Soldier * ptrCurrent;
		Soldier * dummy;
		ptrCurrent = temp;	
		dummy = ptrCurrent->ptrNext ;
		while(ptrCurrent->ptrNext!=NULL)
		{	
			if(dummy->kills > sorter)
			{				
				ptrNew->ptrNext = ptrCurrent->ptrNext;
				ptrNew->kills = sorter;
				ptrCurrent->ptrNext = ptrNew;
				return temp;
			}
			dummy = dummy->ptrNext ;
			ptrCurrent = ptrCurrent->ptrNext;
		}
		ptrNew->kills = sorter;	
		ptrNew->ptrNext=NULL;
		ptrCurrent->ptrNext=ptrNew;						
	}
	return temp;
}
void Soldier::Show(Soldier *temp)
{
	while(temp!=NULL)
	{
		cout << nickname << temp->kills << endl;
		temp = temp->ptrNext;
	}
	
}



void main()
{
	Soldier *first=NULL,l1;
	int choice;
	while(1)
	{
		cout<<"-> [1] Insert Soldier \n-> [2] View Soldiers \n-> [3] Exit\n";
		cin>>choice;

		switch (choice)
		{
		case 1:
			first=l1.Sort(first);
			break;		
		case 2:
			l1.Show(first);
			break;
		case 3:
			exit(0);

		}
	
	}
}

Hi Paynekiller! Welcome to TechTalk!

I just moderate this forum, so I wouldn't be able to help troubleshoot your code, but could you surround your code with [ code] and [ /code] tags? Like this:

Soldier *first=NULL,l1;
int choice;
while(1)
{
cout<<"-> [1] Insert Soldier \n-> [2] View Soldiers \n-> [3] Exit\n";
cin>>choice;

switch (choice)
{
case 1:
first=l1.Sort(first);
break;
case 2:
l1.Show(first);
break;
case 3:
exit(0);

It makes your code easier to read, and you can keep all of the indentation and the formatting that makes the code readible.

done a bit of rehashing and came up with this, it seems to be more on the right track, doesn't it??

i'm getting some parse errors in the addSoldier function, help!

#include <iostream>
#include <string.h>
class Soldier
{
public:
     Soldier(){}
     ~Soldier(){}
     
     void setKills(int setKills){kills = setKills;}
     int getKills(){return kills;}
     
     void setNickname(char setNickname[25]){nickname[25] = setNickname[25];}
     char getNickname(){return nickname[25];}
     
     void setEmail(char setEmail[50]){email[50] = setEmail[50];}
     char getEmail(){return email[50];}
     
     void setRank(char setRank[]);
     char getRank(){return rank[10];}
     
     void Show();

private:
     int kills;
     char rank[10];
     char nickname[25];
     char email[50];
     Soldier * ptrNext;
};

void Soldier::setRank(char setRank[])
{
    if(kills >= 1000)
         char setRank[] = "General";
    if(kills < 1000 && kills >= 500)
         char setRank[] = "Captain";
    if(kills < 500 && kills > 1)
         char setRank[] = "Soldier";
    if(kills <= 1)
         char setRank[] = "Trainee";
    strcpy(rank,setRank);
}

void Soldier::Show()
{
     std::cout << nickname[25] <<  email[50] << kills << rank[10];
}


class LinkedList
{
 public:
        LinkedList(){ptrHead = NULL;}
        Soldier * addSoldier(Soldier *);
        int removeLowest();
        
 private:
        Soldier * ptrHead;
        Soldier * ptrCurrent;
};

Soldier * LinkedList::addSoldier(Soldier * ptrTemp1)
{
        Soldier * ptrNew = new Soldier;
        Soldier * ptrTemp2;
        
        cout << "\nEnter nickname\n";
          char setNickname[25];
          cin >> setNickname;
          ptrNew->setNickname(char setNickname[25]);
        cout << "\nEnter email address\n";
          char setEmail[50];
          cin >> setEmail;
          ptrNew->setEmail(char setEmail[50]);
        cout << "\nEnter number of kills\n";
          int setKills;
          cin >> setKills;
          ptrNew->setKills(int setKills);
}

int LinkedList::removeLowest()
{
       if(ptrHead == NULL)
       {
            std::cout << "No more soldiers to remove!/n";
            return 0;
       }
}

int main()
{
    return 0;
}

Hi,
I am Rammohan from Bangalore and working as a Technical lead in big IT firm .
Solution for your answer is follows:
I have provided you my own sample code for your request: Insert, Reverse, print the list, Sort the list

# include <stdio.h>
# include <stdlib.h>

struct node
{
	int data;
	struct node *link;
};
/* Insert the Value in the List */
struct node *insert(struct node *p, int n)
{
	struct node *temp;
	if(p==NULL)
	{
		p=(struct node *)malloc(sizeof(struct node));
		if(p==NULL)
		{
			printf("Error\n");
			exit(0);
		}
		p-> data = n;
		p-> link = NULL;
	}
	else
		p->link = insert(p->link,n);/* the while loop replaced by recursive call */
	return (p);
}


/* a function to sort reverse list */
struct node *reverse(struct node *p)
{
	struct node *prev, *curr;
	prev = NULL;
	curr = p;
	while (curr != NULL)
	{
		p = p-> link;
		curr-> link = prev;
		prev = curr;
		curr = p;
	}
	return(prev);
}

/* a function to sort a list */
struct node *sortlist(struct node *p)
{
	struct node *temp1,*temp2,*min,*prev,*q;
	q = NULL;
	while(p != NULL)
	{
		prev = NULL;
		min = temp1 = p;
		temp2 = p -> link;
		while ( temp2 != NULL )
		{
			if(min -> data > temp2 -> data)
			{
				min = temp2;
				prev = temp1;
			}
			temp1 = temp2;
			temp2 = temp2-> link;
		}
		if(prev == NULL)
			p = min -> link;
		else
			prev -> link = min -> link;
		min -> link = NULL;
		if( q == NULL)
			q = min; /* moves the node with lowest data value in the list pointed to by p to the list pointed to by q as a first node*/
		else
		{
			temp1 = q;
			/* traverses the list pointed to by q to get pointer to its last node */
			while( temp1 -> link != NULL)
			temp1 = temp1 -> link;
			/* moves the node with lowest data value in the list pointed to by p to the list pointed to by q at the end of list pointed by q*/
			temp1 -> link = min; 
		}
	}
	return (q);
}

void printlist ( struct node *p )
{
	printf("The data values in the list are\n");
	while (p!= NULL)
	{
		printf("%d\t",p-> data);
		p = p-> link;
	}
}

void main()
{
	int n;
	int x;
	struct node *start = NULL ;
	printf("Enter the nodes to be created \n");
	scanf("%d",&n);
	while ( n- > 0 )
	{
		printf( "Enter the data values to be placed in a node\n");
		scanf("%d",&x);
		start = insert ( start, x );
	}
	printf("The created list is\n");
	printlist ( start );
}

Regards,
Rammohan Alampally,
<snip false signature>

commented: Have you got nothing better to do in your "fantastic" job than go bumping fossil linked list threads with your own examples? -4