Hi
$asking_price = "20";
$original_value = "100";
$discount = (1-($askingPrice/$original_value))*100;
echo $discount;why $discount always equal to 100 ?
it supposed to be 80.
ofir0803
0
Light Poster
Recommended Answers
Jump to PostI think that you need to work on your debugging skills! $askingPrice is not the same as $asking_price. $askingPrice = 0 so the result is (1-0)* 100 = 100.
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chrishea
182
Nearly a Posting Virtuoso
I think that you need to work on your debugging skills! $askingPrice is not the same as $asking_price. $askingPrice = 0 so the result is (1-0)* 100 = 100.
ofir0803
0
Light Poster
I think that you need to work on your debugging skills! $askingPrice is not the same as $asking_price. $askingPrice = 0 so the result is (1-0)* 100 = 100.
sorry.
got it
$discount = (1-((int)$asking_price/(int)$original_value))*100;
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