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argv 16 Years Ago by mm-marek …lt;stdio.h> int main (int argc,char *argv[]) { char dvojice[2],c; FILE *soubor; int…; dvojice[0] = argv[2][0]; dvojice[1] = argv[2][1]; if (argv[1]) { soubor = fopen(argv[1],"r"…{ printf("Nepodarilo se otevrit soubor: %s\n",argv[1]); }; } else { printf("Nebyl definovan nazev… Re: argv 16 Years Ago by mm-marek …; if (argc > 1) { dvojice[0] = argv[2][0]; dvojice[1] = argv[2][1]; soubor = fopen(argv[1],"r"); if (soubor…;); } else { printf("Nepodarilo se otevrit soubor: %s\n",argv[1]); }; } else { printf("Nebyl definovan nazev souboru!\n"… Re: argv 16 Years Ago by mm-marek …stdlib.h> int main (int argc,char *argv[]) { char dvojice[2]; FILE *soubor; int i…1) { dvojice[0] = argv[2][0]; dvojice[1] = argv[2][1]; soubor = fopen(argv[1],"r"); if…printf("Nepodarilo se otevrit soubor: %s\n",argv[1]); }; } else { printf("Nebyl definovan nazev… Re: argv 16 Years Ago by mm-marek problem is here works:[CODE] printf("%s\n",argv[2]); //print "ga" [/CODE] didnt work[CODE] printf("%s\n",argv[2][1]); //fall [/CODE] Re: argv 16 Years Ago by VernonDozier … believe, in this line: [code] printf("%s\n",argv[2][1]); //fall [/code] Change "%s" to "…;%c": [code] printf("%c\n",argv[2][1]); //fall [/code] This time you are telling "… Re: argv 16 Years Ago by VernonDozier … and ran without any errors with both the original "argv" lines and the ones you replaced them with (both… Re: argv 16 Years Ago by mm-marek yes, this work... but i still dont know how to fix main problem - i dont want to print argv to screen, i only tested that. Re: *argv help please 15 Years Ago by VernonDozier … out. Any ideas? [CODE] int main(int argc, char *argv[]) { if (argv[1] == "/e") easteregg(); [/code] [/quote] Close… as the previous poster mentioned, test to make sure argv[1] exists by checking argc, and use strcmp. You…[code] if (argc > 1 && strcmp (argv[1], "/e") == 0) easteregg(); [/code] argv 14 Years Ago by squarey … a user has specified a certain argument: [CODE]if (strcmp(argv[i], "-i") == 0) { // do something }[/CODE] I use… for -i is specified: [CODE] if (strcmp(argv[i], "-i") == 0) { if(strcmp(argv[i+1], "") == 0) { //print… Re: *argv help please 15 Years Ago by Duoas …; void easteregg() { ... } int main( int argc, char** argv ) { vector <string> args( argv, argv+argc ); if ((args.size() > 1) and (args… *argv help please 15 Years Ago by ferret_90 … found the easter egg"; } int main(int argc, char *argv[]) { if (argv[1] == "/e") easteregg(); system("TITLE I… Re: *argv help please 15 Years Ago by mahlerfive The line [code]if (argv[1] == "/e")[/code] is invalid since you are compairing a char pointer to a string. To compare strings, use strcmp(). Also, if the user doesn't enter the easteregg argument, you don't want to check argv[1], so first check argc to check the number of arguments. Re: argv 14 Years Ago by Lerner I don't routinely use the command line so this response may be in error, but I don't think so. argc gives the number of arguments passed on the command line and argv the array of strings representing the arguments. So if argc is one the only argument passed is the program itself. If argc is more than that, then something else was passed in. Re: argv 14 Years Ago by strmstn As Lerner said. Check argc first, going further than argv[argc-1] will cause a segmentation fault. argv question! 15 Years Ago by suley04 i just want to know, if you are using an argv statement in your code, and you are defining two files (… like the following?: [CODE] inFile = fopen(argv[data.txt], "r"); outFile = fopen(argv[data.txt], "w"); [/CODE] ....will… Argv query -please help 14 Years Ago by steviebax … the .tif section and replace with .png. The code uses argv[1] to hold the loaded filename - in this case filename….0001.tif. I am then doing ;- std::string op=argv[1]; op+=".png"; write_png(op.c_str(), dst); I… argv[1] when creating an object 12 Years Ago by daino … to write it like this. ` CLASSTYPE FIRSTINSTANCE(argv[1]);` Why would I use argv[1] at all? I'm not sure why… Re: Argv query -please help 14 Years Ago by steviebax … to sort it now with :- size_t found; std::string op=argv[1]; found=op.find_last_of("."); op=op.substr(0… Re: argv[1] when creating an object 12 Years Ago by Ancient Dragon You need to look at the class constructor to see why it need a char*. argv[1] is just whatever you type on the command line folowing the program name. argv decimal to hex 14 Years Ago by peterpanic … -t then do pulse command cmd0 = 0x07; strcpy(timetxt, &argv[1][2]); // put some magic here to get // tstr[0… Re: argv decimal to hex 14 Years Ago by peterpanic … 't': // if -t then do pulse command strcpy(timetxt, &argv[1][2]); time = atoi(timetxt); itoa(time, tstr, 16); When… Re: How would I allow for options to be entered via argv and argc from CMD? 11 Years Ago by deceptikon …#include <stdio.h> int main(int argc, char *argv[]) { int i; for (i = 0; i < argc…; ++i) printf("'%s'\n", argv[i]); return 0; } If the command line contains `$prog…'is a' 'test' Also, don't forget that argv[argv] is guaranteed to be NULL, even if argc is … Re: Problem Printing the whole argv[4] 17 Years Ago by Ancient Dragon argv is a two-diminsional array of strings. [inlinecode]char c[/inlinecode] is only one character, not a pointer to a character array. you need to declare it as [inlinecode]char* a[/inlinecode] in the 3d line following the declaration of main(). Re: help redefine argv ? 13 Years Ago by Auraomega argv is for giving arguments to your program. You're wanting to return arguments so: [CODE]int main(int argc, char **argp) { // create a new 2D array to return value from int **ret; // dynamically allocate memory here (AKA malloc) // return our ret array }[/CODE] This should start you off in the right direction. Re: Interpret "from sys import argv" into english please? 12 Years Ago by valorien argv is a list containing the arguments passed to the python … script: [CODE] # test.py from sys import argv print(argv[0]) print(argv[1]) print(argv[2]) print(argv[3]) [/CODE] command line call: [CODE… Re: Need help about - int main(int argc,char* argv[]) 15 Years Ago by Narue …;argc is the number of arguments Note that argc and argv are simply conventional names. You can change them. In …pointers to char. That's why [ICODE]char *argv[][/ICODE] and [ICODE]char **argv[/ICODE] are equivalent. >a string is an…using the NULL macro in anything except pointer contexts. >argv[0] is always the program name, so argc is … Re: argv 16 Years Ago by Ancient Dragon line 15. Wong check. You need to check argc to see if it is > 1. Then move lines 11 and 12 inside that if statement, between lines 15 and 16. line 18: EOF is an integer, not a char. So you need to redefine variable [b]c[/b] as int, otherwise if you leave it along that loop will never stop. Re: argv 16 Years Ago by mm-marek huh... i see problem... :( im using also dev c++, but on windows vista in text.txt is random text, im trying this exe with text: "gargamel pelmel gar" so, im search "ga" i want to learn t C, so i have bought book and in this is few examples to do... This is one of it. Search in file couple of letters, print in screen and … Re: argv 16 Years Ago by VernonDozier What is the main problem? What is the program supposed to do? What is the program supposed to do that it does not do? What does the program do that it is not supposed to do? Also, what is the revised program (after revisions suggested here)? Re: argv 16 Years Ago by VernonDozier I am going through your program now. So far I see one definite problem. You are using this line: [code] counter ++; [/code] and this line: [code] vysledek[counter]=umisteni; [/code] However, you have never initialized "counter" before using these lines. I believe the run-time error I ran into was because of this. You …