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Re: datediff 13 Years Ago by bigzos '" & DateDiff("yyyy", DateTimePicker1.Text, Now(), FirstDayOfWeek.Monday, FirstWeekOfYear.FirstFourDays) &… Re: datediff 13 Years Ago by G_Waddell I agree you must be entering the wrong syntax... e.g. I want to find the difference between date1 and date2 in *days*, datediff( *day*, date1, date2) I want to know the difference in *Hours* datediff( *hour*, date1, date2) datediff 13 Years Ago by bigzos One of the problems with datediff function is that even if the two dates are 31-12-2011 and 01-01-2012,it will show the difference as 1 year.How to overcome this problem???? Re: datediff 13 Years Ago by poojavb if u are entering the datediff as years then it will show 1 yr as 2011 and 2012 has a diff of 1.... Re: datediff 13 Years Ago by poojavb … New DateTime(2012, 1, 1) Dim days As Long days = DateDiff("d", d1, d2) Debug.Print(days.ToString &… Re: datediff 13 Years Ago by poojavb ….Value Dim Year1 As Integer Dim days As Long days = DateDiff("d", d2, d1) Debug.Print(days.ToString &… Re: datediff 12 Years Ago by guy40az here you go ‘” & Int(DateDiff("d", DateTimePicker1.Text, Now(), FirstDayOfWeek.Monday, FirstWeekOfYear.FirstFourDays) / 365) & "' Re: DateDiff() not showing exact result 17 Years Ago by saini balvinder … and return the exact time difference. using datediff("h"....) datediff("n"....) datediff("s"....) is not working as…h", rdatetime, repdatetime) MM = DateTime.DateDiff("n", rdatetime, repdatetime) SS = DateTime.DateDiff("s", rdatetime, repdatetime) This is… DateDiff() not showing exact result 17 Years Ago by saini balvinder Hello , need some help on following code: HH = DateTime.DateDiff("h", "01/01/2008 12:30:00&…;, "01/01/2008 15:00:00") MM = DateTime.DateDiff("n", "01/01/2008 12:30:00…;, "01/01/2008 15:00:00") SS = DateTime.DateDiff("s", "01/01/2008 12:30:00… dateDiff problem 15 Years Ago by grabit … dynamic. and i am trying to now is use dateDiff to work out the -1 part of the above.…listings WHERE Year(datelisted) = #DatePart("yyyy", Now())# - #dateDiff("yyyy",datelisted,Now())# [/code] in theory this should… that tells me that datelisted is undefined in the dateDiff function Can anyone please help or see another way … datediff in asp.net 14 Years Ago by dougancil … Class _Default Inherits System.Web.UI.Page Public Overloads Function DateDiff(ByVal Interval As [ DateInterval | String ], Dim duration, … = starttimeInput.Text secondDate = endtimeInput.Text msg = durationLabel & DateDiff(DateInterval.Day, Now, secondDate) MsgBox(msg) End Function [/code] … DateDiff() in c#? 13 Years Ago by Andy90 There is DateDiff() function in VB.NET but which function is equivalent to … = Cursor.Position AndAlso LastPointWhenClicked <> Cursor.Position Then If DateDiff(DateInterval.Second, LastTimeMoved, Now) >= 2 Then LastPoint = New Point… Re: datediff 13 Years Ago by poojavb SO how do u want to display the date difference??? in months, year or days??? whatever parameter u will give in the date diff function it will be dependent on that.... Re: datediff 13 Years Ago by Mitja Bonca No, Icannot be, or you did it wrong. Check this example: Dim d1 As New DateTime(2011, 12, 31) Dim d2 As New DateTime(2012, 1, 1) Dim ts As TimeSpan = d2.Subtract(d1) Console.WriteLine("Difference between these two times is:" & vbCr & vbLf & "years: {0}" & vbCr & vbLf & "months: {1}&… Re: datediff 13 Years Ago by bigzos I need it in years in a way that it shows 1 only if actually an year has passed ,,otherwise 0(as with above parameters) Re: datediff 13 Years Ago by bigzos U 're not getting it maybe..I need to get the digit returned and then it will be inserted into column and the two dates are such that one is the current date and other we get from one of the datetimepicker textbox Re: datediff 13 Years Ago by thines01 Can you use DateTime and TimeSpan? They've never failed me. Re: datediff 13 Years Ago by poojavb I have used datetime...in this timespan wont be required...right??? coz he just wants the days.... Re: datediff 13 Years Ago by thines01 When you subtract a DateTime from a DateTime, it creates a TimeSpan. Module Module1 Sub Main() Dim dtOne As New DateTime(2011, 12, 31) '31 Dec, 2011' Dim dtTwo As New DateTime(2012, 1, 1) ' 1 Jan, 2012' Dim tsDiff As TimeSpan = (dtTwo - dtOne) '' System.Diagnostics.Debug.WriteLine(String… Re: datediff 13 Years Ago by poojavb Okkk...after getting the days from the timespan we can apply the condition and get what is required... Re: datediff 12 Years Ago by thines01 Please look into TimeSpan. Re: datediff 12 Years Ago by Reverend Jim In that case you are misusing the term "exact". Unless you mean you want a result of 1 when the difference is exactly one year. If you are not interested in fractions of a year then do as was suggested and find the difference in days then take the integer portion and throw away the rest. That way you get the numbers 0-364 days = 0 years … Re: datediff 12 Years Ago by poojavb Dim BornDate As Date = DateTimePicker3.Value Dim Interval As TimeSpan = Now - BornDate Debug.Print("Interval: " + Interval.TotalDays.ToString) Dim years As Integer = Math.Truncate(Interval.TotalDays / 365) TextBox1.Text = years This part will return exact one year difference if true 'datetimepicker3 is the … troubble with datediff function from database 17 Years Ago by twodayrule … output is [code]mysql_query("SELECT date, datediff('day', date, CURRENTDATE) FROM softwarerepairtable WHERE datediff<= '7' and complete='yes' ");[/code… datebase. i have also tried [code]SELECT * datediff('day', date, CURRENTDATE) FROM softwarerepairtable WHERE datediff<= '7' and complete='yes' ");[/code… Re: troubble with datediff function from database 17 Years Ago by Belrog It seems that you are selecting on the wrong check. You are saying that the function datediff should be less or equal to 7. This is not entirely correct. Perhaps you could try testing on the complete datediff result. How can I get month by using 'DateDiff' function? 14 Years Ago by Kingcoder210 … & "-" & Text3.Text CurDate = Now Text5.Text = DateDiff("yyyy", BDate, CurDate) End Sub My code to…; Text3.Text CurDate = Now Text4.Text = DateDiff("m", BDate, CurDate) Text5.Text = DateDiff("yyyy", BDate, CurDate) End Sub Re: How to use DateDiff calculation around textboxes? Need some help to check code. 14 Years Ago by Teme64 …a textbox [CODE=VB.NET]Dim a As Long a = DateDiff("d", DateTimePicker1.Value.Date, TextBox1.Text)[/CODE] … As Date If Date.TryParse(TextBox1.Text, TempDate1) Then ' Datediff Else ' Not a valid date value End If[/CODE] Last… thing to notice is that DateDiff function returns Long, not an Integer. HTH How to use DateDiff calculation around textboxes? Need some help to check code. 14 Years Ago by dejanc …'s control source like this, and it works: [code] txtDayCalculation =DateDiff("d",txtDateofHire, txtManualDate) txtYear =Int(txtDayCalculation/365) txtMonth…. Anyway, I have write like this: [CODE]me.txtDayCalculation.text = DateDiff("d",txtDateOfHireDateTimePicker, txtManualDateDateTimePicker)[/CODE]. Please someone to check… mysql count records using datediff and where 10 Years Ago by Pravesh_1 I want to count records using datediff() and where condition; I am getting the result with no. … count records with condition; below is the my query SELECT DATEDIFF(CURDATE(), jobs.jobs_listed_date) FROM tbl_first_category AS FIRST , tbl_second_category AS SECOND… Re: How to use DateDiff calculation around textboxes? Need some help to check code. 14 Years Ago by kruxena Hi... The idea of datediff function is to determine how many specified time intervals exist between two date/time values. Are you using two datetimepicker or 1 datetimepicker and a textbox? If your using two datetimepicker, then try the code of Mr. teme64 by using [CODE]datetimepicker.value.date[/CODE]. Let us know if this answers your question.