Search DaniWeb - nextline

Re: Application to save word/sentences to file 8 Years Ago by JamesCherrill nextLine reads lines from a file and returns them to you … Re: nextLine() after nextInt() or nextDouble gives trouble 10 Years Ago by JamesCherrill … it with int num = scanner.nextInt(); String name = scanner.nextLine(); ... and name is an empty String ("")! Here'… in the scanner "\nJohn Doe\n" then nextLine takes everything up to the first \n character - a… This may be difficult if the nextInt and the nextLine are in different areas of code which are not always… nextLine() after nextInt() or nextDouble gives trouble 14 Years Ago by Isky … nextDouble, and try to use nextLine, it won't work unless I put nextLine twice. What's the problem … something for line 1"); String line1 = sc.nextLine(); System.out.println("Type an integer for line …;Type in something for line 3"); String line3 = sc.nextLine(); System.out.println("Line1: " + line1 + "… Re: nextLine() after nextInt() or nextDouble gives trouble 14 Years Ago by BestJewSinceJC …, which leaves the newline in the input stream. But calling nextLine() [I]does[/I] read in newlines, which is why you… had to call nextLine() before your code would work. You could have also called… Re: nextLine() after nextInt() or nextDouble gives trouble 14 Years Ago by Isky … if it's unknown that I'll have a [icode]nextLine()[/icode] after [icode]nextInt()[/icode], how would I be able… function involved. Would I just have to scrap the [icode]nextLine()[/icode] and go with something else? Re: nextLine() after nextInt() or nextDouble gives trouble 11 Years Ago by morrisga2000 … performing like I expected it to. Sure enough, putting in nextLine() twice solved the problem. I think that was is happening… terminating the allocated line of memory, so that when the nextLine() is run it is actually terminating the line that already… Re: nextLine() after nextInt() or nextDouble gives trouble 10 Years Ago by q812717031 i have try some practice and found that whatever nextline() you hava,only the last one can't use.and i don't understand that. Re: nextLine() after nextInt() or nextDouble gives trouble 7 Years Ago by Himanshu_8 … show() `{` Scanner sc = new Scanner(System.in); String s=sc.nextLine(); System.out.println("string is: " + s); `{` `}` nextLine() terminates program 16 Years Ago by Java-Newbie … only accepting the first word. I changed it to input.nextLine() and now it skips that part; it just exits the…¿De que pueblo desea buscar informacion? " ); String pueblo = input.nextLine(); stringPueblo = pueblo.trim(); for ( x = 0 ; x < arregloTotalDatos.length… .nextLine skipping? 13 Years Ago by computercoder …("\nInput a sequence of characters"); String text = console.nextLine(); text = text.toLowerCase(); for (int loop = 0; loop < text… input text. If I change the "String text = console.nextLine();" to "String text = console.next();" then only… Re: nextLine() terminates program 16 Years Ago by lookof2day Have you used Scanner.nextLine()?? Re: nextLine() terminates program 16 Years Ago by Java-Newbie I tried that and got " non-static method nextLine() cannot be referenced from a static context". Thanks... :-) Re: nextLine() terminates program 16 Years Ago by lookof2day if you didn't got the exception here [code] nombreDocTXT = input.next(); [/code] then you can't get it when calling nextLine(); because it's just another method of Scanner class. However, can you provide your updated code that threw exception?? Re: nextLine() terminates program 16 Years Ago by lookof2day … informacion? " ); input = new Scanner(System.in); String pueblo = input.nextLine(); It will work. I'm still trying to know the… Re: .nextLine skipping? 13 Years Ago by Ezzaral …. [B]> If I change the "String text = console.nextLine();" to "String text = console.next();" then only… weird in.nextLine behavior 13 Years Ago by Geowil …;Please enter the address of the person:"); address = in.nextLine(); //Get Address dAddress[i] = address; //Set current element to address…] + " " + dDonationTimes[x] + " (Yes/No)"); uChoice2 = in2.nextLine(); System.out.println(); if ((uChoice2) .equals ("Yes")) { System… Re: weird in.nextLine behavior 13 Years Ago by masijade …; the newline that follows it, so if you use "nextLine" after using something like nextInt() you will get whatever…) then call nextInt (or whatever) and follow it immediately with nextLine (again, assuming you are only expecting a single input on… Issue with nextLine() 14 Years Ago by redlyfs ….out.print("Enter book title : "); bTitle = input.nextLine(); System.out.print("Enter book type ( NA / A)… : "); bType = input.nextLine(); System.out.print("Enter book author : "); bAuthor = … Scanner nextLine() Stops at Number? 11 Years Ago by coolbeanbob … 33 in PrefixCalc.java) calc = new ExpressionTree(new Scanner(console.nextLine())); When I run the program and enter "4 + 8… separated by blanks"); calc = new ExpressionTree(new Scanner(console.nextLine())); } System.out.println("\nInput as prefix expression:"); calc… Scanner nextLine() not letting me type anything 13 Years Ago by plasticfood ….println("what is your name? "); String name = kb.nextLine(); boolean x = Member.checkMember(name); System.out.println(x); } [/CODE… Help with my GroupProgram 12 Years Ago by cloud02 …("\nPress enter to continue. . ."); kbd.nextLine(); break; case 3: showJailInterns(sortJailInternsAccordingToNames(intns)); System.out…println("\nPress enter to continue. . ."); kbd.nextLine(); break; case 4: showJailInterns(sortJailInternsAccordingToRoomNumbers(intns)); System.out… Re: Help with my GroupProgram 12 Years Ago by cloud02 …quot;\nPress enter to continue. . ."); kbd.nextLine(); break; case 3: showJailInterns(sortJailInternsAccordingToNames(intns)); System.out…("\nPress enter to continue. . ."); kbd.nextLine(); break; case 4: showJailInterns(sortJailInternsAccordingToRoomNumbers(intns)); System.out… Assembler 12 Years Ago by samidha …); while(nextline[i]!='\n'&&nextline[i]!=EOF) { if(!isalnum(nextline[i])) nextline[i]=' '; else nextline[i]=toupper(nextline[i]); i++; nextline[i]=fgetc(ptr1); } nextline[i… Re: Help with Inventory Program 12 Years Ago by YiJun … file to create:"); fileName = keyboardScanner.next(); //consume nextLine character keyboardScanner.nextLine(); //Create a new file object with given name f…lt;enter> to quit"); //get line from user; //nextLine = keyboardScanner.nextLine(); //write line to file; //listSort(); for (int i = … problem in working with object arrays in a package 11 Years Ago by radhika1990 …out.println("Name:-"); ob0.name=obj.nextLine(); System.out.println("Patient ID:-"); …quot;Last Appointment Date:-"); ob0.ladate=obj.nextLine(); System.out.println("Age:-"); ob0…out.println("Name:-"); ob0.name=obj.nextLine(); System.out.println("Patient ID:-"); … Error Scanner Loading 14 Years Ago by killerqb … intsec = intsec - (60 * minute); } String stringURL = load1.nextLine(); Song song = new Song(tempName, tempArtist, intmin, intsec, stringURL);… = intsec - (60 * minute); } // String stringURL = load.nextLine(); Song song = new Song(tempName, tempArtist, intmin, intsec); this.songList… Issue creating array with booleans. 14 Years Ago by SilentDuck …() { //Declare variables bool line[78]; bool nextLine[78]; void firstline(); void coutline(); void rules();… //Declare variables bool line[78]; int x; bool nextLine[78]; for (x=1; x < 78;… 1 && line [x+1] == 1) nextLine[x] = 0; //rule 2 else if (line[x… trying to call a class in another class 14 Years Ago by nici0306 …()) { System.out.print("Subject: "); subject = scanner.nextLine(); m.setSubject(subject); } if ( emailText.isEmpty()) { System.out….print("Body: "); emailText = scanner.nextLine(); m.setEmailtext(emailText); } } //getting the SMTP server from … How should i implement these functions ? 12 Years Ago by Mr. pen …("Enter the District Name :"); String districtN = input.nextLine(); System.out.println("Enter the Region Name :"); String….println("Enter the Region Name :"); String regionN = input.nextLine(); } } [/CODE] [CODE] import java.util.*; public class main { public … Re: Issue creating array with booleans. 14 Years Ago by SilentDuck …[x] == 1 && rules[x+1] == 1) nextLine[x] = 0; //rule 2 if (rules[x-1] ==…[x] == 1 && rules[x+1] == 0) nextLine[x] = 0; //rule 3 if (rules[x-1] ==…[x] == 0 && rules[x+1] == 0) nextLine[x] = 1; //rule 5 if (rules[x-1] ==…