[perfect-numbers] Forum Topics

Well I have created this one and on my computer it is working. I would like to hear about some alternative solutions. INTRODUCTION This time I have one algorithm, but to understand it we need to consider a few terms. First of all, we should be familiar with the pangrams. …

Hey everyone, I am having trouble on this one practice problem. It is a question that requires another question I already completed to solve this one. The qusetion is "Implement a method allPerfect() that takes an integer parameter end. The method prints every perfect number from 1 to end. Use …

Hello, I'm trying to write a program using MIPS Assembly Language (I write the code in TextWrangler and run it in QTSpim) I was wondering how I would go about checking if a number is perfect or not. I know my first lines of code may be partially incorrect but …

I want to be able to write a program that repeatedly prompts the user to enter an integer. The program determines if that numbers is perfect and then writes out a message saying if it is or not, then prompts once again. I'll end the loop (and the entire program …

A number is called a proper divisor of N if M < N and M divides N. A positive integer is called perfect if it is the sum of its positive proper divisors. For example, the positive proper divisors of 28 are 1, 2, 4, 7, and 14 and 1+2+4+7+14=28. …

[CODE]#include<stdio.h> int main() { int n,i,c=0; printf("\nEnter a no:"); scanf("%d",&n); for(i=1;i<n;i++) { if(n%i==0) { c=c+i; } } if(n==c) printf("\nPerfect no."); else printf("\nNot a perfect no."); }[/CODE]

For this code i am inputing one number and trying to see if it is a perfect number [CODE]#include<iostream> #include<cmath> #include<iomanip> #include<conio.h> using namespace std; void perfect(int); int isfactor(int, int); int N, i; int main() { perfect(N); isfactor(N, i); } int isfactor(int number, int divisor) { if(number%divisor==0) return 1; else …