Like most modern languages Swift has sets and set operations. Here is a quick look. Coming in the fall of 2015 ... Swift2 replaces println() with just print() that has a newline default. The sort of thing that Python3 did to print(). There are some other syntax changes. Good news, there will be a Swift 1-to-2 migrator utility to change Swift1 syntax to Swift2 syntax. |
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I've been looking around for an answer to this but have had no luck. I need to take two files and print the top most frequent words they have in common as well as their combined(sum) frequencies. This might be simple but I'm pretty new to programming. Any help? def mostFrequent(word,frequency,n): my_list = zip(word,frequency) #combine the two lists my_list.sort(key=lambda x:x[1],reverse=True) #sort by freq words,freqs = zip(*my_list[:n]) #take the top n entries and split back to seperate lists return words, freqs #return our most frequent words in order from wordFrequencies import * #gives both the word and its frequency in a … |
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---------------------------------------------TSet.h------------------------------------------------------ #include <iostream> using namespace std; template <class V> class TSet { public: TSet(); TSet(int size); ~TSet(); void add(V new_item); void remove(V item_to_remove); int num_of_items(); bool isFull(); bool is_item_in_set(V item); friend bool operator==(const TSet<V>& left, const TSet<V>& right); friend bool operator!=(const TSet<V>& left, const TSet<V>& right); friend ostream& operator<<(ostream& outs,const TSet<V>& list); private: V *item_list; int size_of_list; int current_size; }; ----------------------------------------TSet.cpp----------------------------------------- #include <iostream> #include "TSet.h" using namespace std; template<class V> TSet<V>::TSet() : size_of_list(0), current_size(0) { item_list = new V[0]; } template<class V> TSet<V>::TSet(int size) : size_of_list(size), current_size(0) { item_list = new V[size]; } template<class V> TSet<V>::~TSet() { delete [] item_list; … |
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For any integer n > 1, if Al, A2, A3, ... , An, and B are any sets, then (A1 -B) (A2 -B) ... (An -B) = (Al A2 A3 … An) -B. I was able to prove for all sets A, B, and C, (A -B)(C -B)= (AC) - B, and for the above I know that's it's true based on the just mentioned proof but I am having a hard time actually proving it. What steps would I take? I am not looking for an answer just a push in the right direction. Thanks. |
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Hi, my question is simply but a little bit tricky; let assume that there are two array array1 = (2, 5, 6, 1, 7) and array2 (3, 2, 6, 8) and after function setUnion new array or use pointer return (2, 5, 6, 1, 7, 3, 8). Below my code is shown my problem is I found (2, 5, 6, 1, 7, [B]8[/B], [B]8[/B]) How I fix this problem ? Here my code include main function:: [CODE] #include <iostream> using namespace std; void setUnion (const int array1[], const int size1, const int array2[], const int size2, int &newSize, int *&unionArray) … |
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I have a series of Key value pairs. Each Key has 2 values. Values of Keys ma coincide. Initially i start with Key1, ValueKey1, ValueKey2 are stored in a set.(Maybe Array). Now for each consecutive Keyi, i check if Valuei, Valuei+1 are in the set. If any one of them is in the set, then join the set. Else if both KeyValues are present in a set, discard that key . How can i implement this thing using C++, i have very less idea, so i would suggest if possible a code snippet or a hint would be really helpful. … |
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Hi, I have an expression tree in which the nodes are operators (union, intersection etc represented by a string "/u") or the nodes are std::sets. How could I access the std::set's values in order to carry out the tree evaluation using the operator functions(set_union(), set_intersection() etc) ? The expressions are pre and postfix. Thanks for any help, it's most appreciated. |
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HEllo this is reaaally urgent, the deadline is within less than an hour and thirty minute, and I lost hope that I can fix the problem myself. I know it has to do with pointers and allocating memory dynamically. The assignment was to use operator overloading to add two sets (adding two sets by getting the union of the two sets, which means all the elements in both set but not repeated). I figured out a way to do so but I think this memory problem is the cause why it's not working here is the constructor of the class … |
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I get the following message when executing a stored procedure. [COLOR="Red"]The query has exceeded the maximum number of result sets that can be displayed in the results grid. Only the first 100 result sets are displayed in the grid.[/COLOR] However , i cannot change the fact that the SP uses a cursor. Basically what happens is that the SP executes into a declared table, and then for each row it executes a new stored procedure bringing the number of result sets to about 20 000.... Any advice on where i can change this setting ? Regards, |
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What are the basic skill sets necessary for a person to handle SEO initiatives for a corporate website? I am curious because one of my clients is looking to hire someone in a permanent role. Currently I am handling their SEO intiatives and they feel that as I am the closest to the role I should play a role in the hiring process so I am looking for some thoughts and input. Thanks. |
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The End.