dina85

Help me positioning three divs, next to each other? my code doesn't work.. why 'merah' div display after 'biru' div content. what's wrong with my code? <div class="kuning"> Kuning </div> <div class="kelabu"> <div class="hijau"> Hijau </div> <div class="biru"> Biru <br /> sdaddfcdsf fdfdfdf dfdfsfsd fdfsdfs <br/> dadads dsdssssssssssssss sssssssssss <br …

i need to update ADMIN COLUMN with $_SESSION variable. however, it does not seem to be working correctly. why? help me plz... require("conn.php"); $sql = "select * from pemohon where id='$_GET[id]';"; $result = mysql_query($sql); while($row = mysql_fetch_array($result)) { $sn = $_SESSION['SESS_NAME']; $sql = "update pemohon set admin='$sn',status_key='2' where id='$_GET[id]';"; $result …

what's wrong with my code at line 6, it's give blank page, the output can't display. $kp = $_POST['kp']; $kp2 = $_POST['kp2']; $kp3 = $_POST['kp3']; require("conn.php"); $sql = "select * from pemohon where kp_baru='$kp' AND kp_baru2='$kp2' AND kp_baru3='$kp3'";

require("conn.php"); $sql = "select * from pemohon where kp_baru='$kp';"; $result = mysql_query($sql); while($row = mysql_fetch_array($result)) { if($row == TRUE) { echo $row['kp_baru']; // can display } else { echo "No KP tiada didalam pangkalan data."; // can't display } }

i want to print out my form using onClick="window.print()".. but the output is not same with display form in browser. for the information, i use CSS to positioning the layer or <div>..

I need to use javascript so that when the one radio button is selected nothing happens but if the other one is (for example, Cheque) it will then validate the field (Cheque Number)..

how to make javascript validation onsubmit go first before onclick submit button <form name="daftar" method="post" action="daftar.php" onsubmit="return checkscript()"> <input type="submit" name="Daftar" value="Daftar" id="submit" onClick="return tq()"/> and my js: function checkscript() { if (document.daftar.terms.checked == false) { alert('Sila pastikan anda telah check ruangan persetujuan, untuk menandakan anda setuju dengan syarat-syarat kami.'); …

after press submit button to upload the image, the information will display at new window, i need the information will be display below submit button. my code: <?php if($_GET['action'] == "upload") { ?> <div id="upload"> <br/><br/> <form action="upload_image.php?action=upload" method="post" enctype="multipart/form-data"> <label for="file">Gambar yang ingin dimuat naik:</label> <input type="file" name="file" id="file"><br><br/> …

can't download file from database, got error, help me please.. <?php require("conn2.php"); $sql="select image from images where id='$_GET[id]';"; $result = mysql_query($sql); $row = mysql_fetch_array($result) $name = $row['image']; // the name of the file that is downloaded $FilePath = "upload"; // the folder of the file that is downloaded , you …