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I'm getting this error in one of my scripts: **You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '-25,25' at line 1** Below is part of the code any help would be great <?php … 
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The code below is working fine in that it is showing the correct results from the DB, however I would like to change the way the link looks in the URL, currently after being submitted after choosing from the dropdown, it results in: **mysitecom/wallpapers/browse.php?pcat=Cars** I want the URL to look … 
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I'm trying to have my code display all pictures for a specific ID, this is the current code that is only showing a single picture to be displayed, how can I get it to display the others as well? thanks [CODE]<?php $id=$_REQUEST['id']; $result=mysql_query("SELECT * FROM gallery_work_thumbnail WHERE id=$id"); while($row=mysql_fetch_array($result)) { … 
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