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I have two tables like below tb1 Date Cr Dr 2018-04-29 100 50 2018-04-30 0 150 2018-05-01 250 100 2018-05-02 150 100 2018-06-10 300 250 2018-06-11 0 50 tb2 Date Cr 2018-05-01 350 2018-05-02 250 2018-06-10 300 2018-06-11 100 2018-06-15 200 2018-06-18 100 I need the following Result Apr May …

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I am trying to get access toke from FB through Developer App. But I am not able to json_decode the call back response. If I use the token_url call from browser, it returns the access token. But from within the script it does work. I searched online and foun that …

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My code is include "src\whatsprot.class.php"; $username = "91xxxxxxxxxxxx"; //Mobile Phone prefixed with country code so for india it will be 91xxxxxxxx $password = "password"; $identity = strtolower(urlencode(sha1($username, true))); $w = new WhatsProt($username, $identity, "WhatsApp Messaging", true); But This part of the code $w = new WhatsProt($username, $identity, "WhatsApp Messaging", true); …

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I dont know whether this is the relevant forum but I dont know why I am getting the above mentioned error when I try to open website www.magicbricks.com from my laptop. I can open this on my office computer..! The error details are as below; HTTP Status 500 - error.security.userNotActive …

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I am trying to use a sms gateway app for android called SMSGateway with a http header request using curl as below; $curl_handle=curl_init(); curl_setopt($curl_handle, CURLOPT_URL,"http://192.168.1.2:9090/sendsms?phone=$phone&text=$message1&password=xxxxxxxx"); curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 10000); curl_setopt($curl_handle, CURLOPT_TIMEOUT,50000); curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1); curl_setopt($curl_handle, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows NT 6.1; rv:36.0) Gecko/20100101 Firefox/36.0'); $query = curl_exec($curl_handle); if($query){echo "Message Sent to $phone …

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I have a page where it allows my users to upload their videos through an html5 file upload form and a PHP script that saves file in a folder on server. All works fine. But when it is displayed using video tag, it simply does not play ! I do …

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I have no issues with the query in the below code. But the second code is throwing the error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 Working code …

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I have no issues with the query in the below code. But the second code is throwing the error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 Working code …

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I am at my wits end ! Dont know what's wrong with the following code. It is always saying "Parse error: syntax error, unexpected $end in C:\Program Files\EasyPHP-5.3.6.0\www\addallbuy.php on line 51" [CODE] <?Php mysql_connect("localhost","root"); mysql_select_db("landshop_clientdata"); $Date = Date("Y-m-d"); $Agt="Landshoppe"; $user="anitg"; $Title="Mr."; $first="Anit"; $last="Gopinath"; $Age="40"; $prop="Wanted 1 BHK/2BHK and other properties"; …

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