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 | hi all, how do i use a drop down box to show my fields in my sql table ? below is what i have so far, i need to display all of the EmployeeIDs in the drop down box. [CODE]<select name="name"> <?php $sqlName="SELECT * FROM employeedetails"; $queryName = mysql_query($sqlName,$connection); $recordName …  |
| | below is my code to use chekc boxes to update my status field to either a 1 or 2, but altohught it doesnt show any errors, it wont update HELP PLZ </style> </head> <body> <table width="744" height="536" border="1"> <tr> <td height="63" colspan="4" bgcolor="#8BCB6A"><p><img src="CO-OP title.gif" width="407" height="64" /> <?php $connection=mysql_connect('localhost','but09081489',''); … |
| | Hi all, im currently trying to create a news feed, i have the basis of the code, as i can enter information and it is displayed on a different webpage, but i need all of the different updates to be displayed, and need a scroll bar so they can be … |
| | Hi all, im trying to make a new webpage open if a persons password is equall to COOP, i have used the code [CODE]header('Location: loginfull.php')[/CODE] to do this but i need to call through the EmployeeID and Password when this link is opened, any one have any idea how ? … |
| | Hi all , below is a program i have made, and i need to know the code to compare password and password1 so they are the same value and the user hasn't made a mistake, but im not sure on how to do this, any ideas ? [CODE]<body> <table width="744" … |