Posts
 
Reputation
Joined
Last Seen
0 Reputation Points
Unknown Quality Score

No one has voted on any posts yet. Votes from other community members are used to determine a member's reputation amongst their peers.

~2K People Reached
Favorite Forums
Favorite Tags
Member Avatar for goltu

Please help me i do not want to show successfully message in again insertation in page. [CODE] protected void Button1_Click(object sender, EventArgs e) { try { string constr; constr = WebConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString; SqlConnection con = new SqlConnection(constr); con.Open(); string str = "insert into Doe_detail values('" + TextBox1.Text + "','" + TextBox2.Text …

Member Avatar for sufyan2011
0
86
Member Avatar for goltu

[CODE]<asp:TextBox ID="TextBox3" runat="server" ReadOnly="True" ></asp:TextBox> <asp:CalendarExtender ID="CalendarExtender2" TargetControlID="TextBox3" runat="server"> [/CODE] I have use text box and calender

Member Avatar for bhartman21
0
114
Member Avatar for goltu

[CODE] <%@ Page Language="C#" MasterPageFile="~/Admin.master" AutoEventWireup="true" CodeFile="last_try.aspx.cs" Inherits="last_try" Title="Untitled Page" %> <%@ Register Assembly="AjaxControlToolkit" Namespace="AjaxControlToolkit" TagPrefix="asp" %> <asp:Content ID="Content1" ContentPlaceHolderID="ContentPlaceHolder1" Runat="Server"> <asp:ToolkitScriptManager ID="ToolkitScriptManager1" runat="server"> </asp:ToolkitScriptManager> <asp:UpdatePanel ID="UpdatePanel1" runat="server"> <ContentTemplate> <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False" AllowPaging="True" DataSourceID="SqlDataSource1" onselectedindexchanged="GridView1_SelectedIndexChanged" onrowcommand="GridView1_RowCommand" > <Columns> <asp:BoundField DataField="l_no" HeaderText="l_no" SortExpression="l_no" /> <asp:BoundField DataField="nam_dep" HeaderText="nam_dep" SortExpression="nam_dep" /> <asp:BoundField …

0
69
Member Avatar for goltu

I created two parentgridview and childgridview . [CODE] <asp:GridView ID="ParentGridView" runat="server" AutoGenerateColumns="False" DataSourceID="SqlDataSource1" DataKeyNames="l_no" onselectedindexchanged="ParentGridView_SelectedIndexChanged"> Columns> <asp:TemplateField HeaderText="Letter Number"> <ItemTemplate> <asp:Label id="l_no" Runat="Server" Text='<%# Eval("l_no") %>'/> </ItemTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="name Department"> <ItemTemplate> <asp:Label id="nam_dep" Runat="Server" Text='<%# Eval("nam_dep") %>'/> </ItemTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="View"> <ItemTemplate> <asp:Button ID="ViewChild_Button" runat="server" Text="+" CommandName="Edit" /> </ItemTemplate> …

Member Avatar for sufyan2011
0
143
Member Avatar for goltu
Member Avatar for goltu

I am able to succesful creating dynmically dropdownlist but i cannot use it seleted change event Mainly problem [CODE] for (int i = 0; i < DDLCount; i++) { // Create the dropdownlists ddl = new DropDownList(); la = new Label(); //DropDownList dd2 = new DropDownList(); ddl.ID = "Text" + …

0
89
Member Avatar for goltu

Dyanmically created no of dropdownlist IN it s seletedchange index event i wrote code i want that if seleted any value in dropdown its correspons value would be come in label or textbox from database .

0
55
Member Avatar for goltu

[CODE]It suceesful in first time you enter number .But if remove that umber again enter it is adding . Like first input 4 in textbox and enter .remove that number textbox input 6 and enter . it "adding 4+6" 4 alright plus new 6 more will display means totally 10 …

0
74
Member Avatar for goltu

First in web form THere will appear one textbox and button. enter the number in textbox and press the button.Pressing button create Dynamically t number of dropdownlist as entered in textbox.I successful do it .But when i what use the seletedvalue of dropdownlist I cannot through anthor buttton . I …

Member Avatar for goltu
0
910