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Member Avatar for trickist17

Can please someone tell me, why I always get SECURITY_ERR when trying to open a new filesystem? The code is from html5rocks.com, so it is probably not the code. Chrome Version: 19.0.1084.15 (Developer Built). Code (from [html5rocks.com](http://www.html5rocks.com)): <html> <head> <style> .example { padding: 10px; border: 1px solid #CCC; } #example-list-fs …

Member Avatar for trickist17
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Member Avatar for trickist17

[CODE] /*the ø stands for document.getElementById*/ function conwidth(){ var a=document.getElementsByClassName('dropdown'); var e=[]; for(i=0;i<=a.length;i++){ if(a[i].innerHTML.length>28){ /*Safari Error (only if I bypass the setwid(j,k)command): TypeError: 'undefined' is not an object (evaluating 'a[i].innerHTML')*/ e.push(a[i].innerHTML); var j=ø(a[i].parentNode.id).parentNode.id; var k=200+8*(a[i].innerHTML.length-28); setwid(j,k); } } } function setwid(b,c){ var dr=document.getElementsByClassName('dropdown');var st=document.getElementsByClassName('strich');var a=function(a){return ø(a.parentNode.id).parentNode.id;}; /*Safari Error: TypeError: 'undefined' …

Member Avatar for trickist17
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Member Avatar for trickist17

I have an element in my html-code, that holds a completely new html code written by a user, for previewing after codeing into a textarea (simple: a web-editor). My problem starts when the user types in his code with an id or/and a class, that is already in my code. …

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Member Avatar for trickist17

Hey, I'm trying to do a loop in javascript, that adds an array into a variable. Because it is a bit hard to explain exactly what I want, please look at this code, which does the (for the beginning) same. [CODE] var s="one, two, three"; //this can be changed var …

Member Avatar for Troy III
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Member Avatar for trickist17

Hello, I have a problem with the response text of an ajax request. I want to use the answer of the php script ("true" or "false") to do different things with a if-condition, but it always takes the false option. Here is the code. [CODE] var hr = new XMLHttpRequest(); …

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Member Avatar for kirtan_thakkar

Thank you so much for this, great idea! Now I am totally new to PHP and I want to overwrite the value for a name with a variable [I]$newvalue[/I]. Somebody has an idea? Probably very easy, but it's just too high for me at the moment. Thank you!

Member Avatar for trickist17
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The End.