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Hi All, I want to pass few dynamic arguments to shell script. The number of arguments differ each time I call the script. I want to print the arguments using the for loop as below. But not working out. for (( i=1; i<=$#; i++ )) do echo $"($i)" done /bin/sh …

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Member Avatar for laalesh

Hi All, I want to pass few dynamic arguments to shell script. The number of arguments differ each time I call the script. I want to print the arguments using the for loop as below. But not working out. for (( i=1; i<=$#; i++ )) do echo $"($i)" done /bin/sh …

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