Hi,

Assume, I have table which consists of 5 values, say

C:/Testing/test1/
C:/Testing/test1/test2/
C:/Testing/1/
C:/Testing/
C:/1/


I want to query the database table to get the values starts from 'C:/Testing/' and '/' as a escape character.

ie, I want to get only two things,

C:/Testing/test1/
C:/Testing/1/

Both starts with 'C:/Testing/' and the next escape character is '/' .

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Similarly, if query the database which starts with 'C:/' it should give the following details:

C:/Testing/
C:/1/


I have tried LIKE query and REGEXP queries. But seems no luck.

Could any one update me, is there any way to do it.

Thanks in Advance,
Rahul.

$sql = Select * from `table` WHERE `column`like 'c:/testing/%' LIMIT 2?

Is this what you want to achieve?

Thanks for your reply.

But that is not my requirement.

If you put Like query means, it will list all the items.. Even if you put limit , it wont work, if I get results by ascending or descending order.

I put those values (say C:/Testing....) as a sample examples.

My requirement is, the result set should starts with a string (say C:/) and it should ends with the next escape character '/'.

Hence it should only return,

C:/Testing/
C:/1/

ie, strings Starts with 'C:/' and some characters and then ends with '/'.

The query should not list the other values like,

C:/Testing/test1/
C:/Testing/test1/test2/
C:/Testing/1/

Because, the above strings contain two escape characters ('/') after 'C:/'

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For an example,

if we put like query with like query with 'C:/%' it will return all the text which starts with 'C:/' . What I need is, if we put like with 'C:/%/' , ie, starts with 'C:/' and should ends with the next '/' character. ie, Taking '/' as a escape character for like '%' query.

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Hope, you understand my requirement with this email.

Awaiting your update.

Oh now i Understand What you are trying to do!

Sorry, I don't know how to achieve it with mysql (I think it's not possible)

How about fetching all rows in a array, and then unset those who have more than 2 slashes! (C:/test/)

Yes, Currently I am doing the same you have mentioned. ie, Get all those things in a array, and get the correct values.

I will continue my work. If you know it later, please reply to this thread.

And once again, thanks for your inputs.

Well i think it's better so!

as far as I know letting PHP handle them is faster than querying the db with a lot of where/like conditions!

Yes, but if there is a lot of sub directories then querying with 'like' will avoid unwanted data processing.

Anyway thanks for your inputs.

Hi,

I found a sample query..

select SUBSTRING_INDEX(COLUMN, '/', -4) like 'C:/Testing/%/';

It should return the value that I required.

where -4, if no. of slashes + 1.