Sometimes when you get a large check from your employer, the value is written out in words. I get those all the time of course. So I wrote this little Python code to convert an integer value to english words. Numbers as high as 999 vigintillion can be used. In case you don't know, a vigintillion is 10 to the power 60. That is what our national deficit will be soon.

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``````# integer number to english word conversion
# can be used for numbers as large as 999 vigintillion
# (vigintillion --> 10 to the power 60)
# tested with Python24      vegaseat      07dec2006

def int2word(n):
"""
convert an integer number n into a string of english words
"""
# break the number into groups of 3 digits using slicing
# each group representing hundred, thousand, million, billion, ...
n3 = []
r1 = ""
# create numeric string
ns = str(n)
for k in range(3, 33, 3):
r = ns[-k:]
q = len(ns) - k
# break if end of ns has been reached
if q < -2:
break
else:
if  q >= 0:
n3.append(int(r[:3]))
elif q >= -1:
n3.append(int(r[:2]))
elif q >= -2:
n3.append(int(r[:1]))
r1 = r

#print n3  # test

# break each group of 3 digits into
# ones, tens/twenties, hundreds
# and form a string
nw = ""
for i, x in enumerate(n3):
b1 = x % 10
b2 = (x % 100)//10
b3 = (x % 1000)//100
#print b1, b2, b3  # test
if x == 0:
continue  # skip
else:
t = thousands[i]
if b2 == 0:
nw = ones[b1] + t + nw
elif b2 == 1:
nw = tens[b1] + t + nw
elif b2 > 1:
nw = twenties[b2] + ones[b1] + t + nw
if b3 > 0:
nw = ones[b3] + "hundred " + nw
return nw

############# globals ################

ones = ["", "one ","two ","three ","four ", "five ",
"six ","seven ","eight ","nine "]

tens = ["ten ","eleven ","twelve ","thirteen ", "fourteen ",
"fifteen ","sixteen ","seventeen ","eighteen ","nineteen "]

twenties = ["","","twenty ","thirty ","forty ",
"fifty ","sixty ","seventy ","eighty ","ninety "]

thousands = ["","thousand ","million ", "billion ", "trillion ",
"quadrillion ", "quintillion ", "sextillion ", "septillion ","octillion ",
"nonillion ", "decillion ", "undecillion ", "duodecillion ", "tredecillion ",
"quattuordecillion ", "quindecillion", "sexdecillion ", "septendecillion ",
"octodecillion ", "novemdecillion ", "vigintillion "]

if __name__ == '__main__':
# select an integer number n for testing or get it from user input
#n = 4321234567890
#n = 1111111111111
#n = 1234567890123
n = 1001000100100111
#n = 1

print n

print "-"*50
print int2word(n)
print "-"*50``````
About the Author

Scientist

``````units = ["", "one", "two", "three", "four",  "five",
"six", "seven", "eight", "nine "]

teens = ["", "eleven", "twelve", "thirteen",  "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]

tens = ["", "ten", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"]

thousands = ["","thousand", "million",  "billion",  "trillion",
"quadrillion",  "quintillion",  "sextillion",  "septillion", "octillion",
"nonillion",  "decillion",  "undecillion",  "duodecillion",  "tredecillion",
"quattuordecillion",  "sexdecillion",  "septendecillion",  "octodecillion",
"novemdecillion",  "vigintillion "]

def numToWords(num):
words = []
if num == 0:
words.append("zero")
else:
numStr = "%d" % num
numStrLen = len(numStr)
groups = (numStrLen + 2) / 3
numStr = numStr.zfill(groups * 3)
for i in range(0, groups*3, 3):
h = int(numStr[i])
t = int(numStr[i+1])
u = int(numStr[i+2])
g = groups - (i / 3 + 1)

if h >= 1:
words.append(units[h])
words.append("hundred")

if t > 1:
words.append(tens[t])
if u >= 1:
words.append(units[u])
elif t == 1:
if u >= 1:
words.append(teens[u])
else:
words.append(tens[t])
else:
if u >= 1:
words.append(units[u])

if g >= 1 and (h + t + u) > 0:
words.append(thousands[g])

return words

print numToWords(1000000000)
print " ".join(numToWords(1001000025))
print numToWords(0)``````

FYI, all of the other posts missed quindecillion, so any numbers above quattuordecillion are off.

``````scales = ["hundred", "thousand", "million", "billion", "trillion",
"quadrillion",  "quintillion",  "sextillion",  "septillion", "octillion",
"nonillion",  "decillion",  "undecillion",  "duodecillion",  "tredecillion",
"quattuordecillion", "quindecillion", "sexdecillion",  "septendecillion",  "octodecillion",
"novemdecillion",  "vigintillion"]
``````

nickruiz, sharp eye, thank you!
I corrected it.

Nice job it has been of great help to me to tackle my project. One love..