Another task from C++ forum is trivial in Python even taking handicap of not using Counter.

"""Count nonoverlapping consecutive three digit numbers inside string
   without using modules


s = '[@@@123124123123125@@@]'
f = next(n for n,c in enumerate(s) if c.isdigit())
numbers = (s for s in (''.join(x) for x in zip(s[f::3], s[f+1::3], s[f+2::3])) if s.isdigit())
counts = {}
for n in numbers:
    counts[n] = counts.setdefault(n, 0) + 1
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IT Pro doing Eng-Fin-Eng translations