Python Get Root Floor and Root Ceiling of a Number

Also because of my work in number theory, I often need to have the root floor and root ceing of a number.

This is my function for computing those two numbers from a target number.

# Imports #
import sys, os, importlib, inspect, locale, time, math
from datetime import datetime
locale.setlocale(locale.LC_ALL, '') # Set the locale for your system 'en_US.UTF-8'


    # Main #
def main():
        # Main Code
    print("Root floor: {}, Ceiling: {}".format(*f_RootSplit(91)))
    print("Root floor: {}, Ceiling: {}".format(*f_RootSplit(161)))

#-----------Basement------------

    # Functions #
        # Normal Functions
def f_RootSplit(v_Num):
    """&Syntax: INT; Returns: LIST of INT;
    Desc.: Converts v_Num into root floor and root ceiling.
    Test: print("Root floor: {}, Ceiling: {}".format(*f_RootSplit(91)))"""
    v_RootFloor = math.sqrt(v_Num) // 1 ## Compute sqrt floor
    v_RootCeiling = v_RootFloor + 1 ## Create sqrt ceiling
    return v_RootFloor, v_RootCeiling

    # Main Loop #
if __name__ == '__main__':
    main()

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2 Years Ago

Last Post by vegaseat

Why not use math.floor() and math.ceil() ?

Try ...

sf = "For {} Root floor: {}, Ceiling: {}"
n = 91
print(sf.format(n, math.floor(n**0.5), math.ceil(n**0.5)))
n = 161
print(sf.format(n, math.floor(n**0.5), math.ceil(n**0.5)))

floor python root

Why doesn't the code (2) below produce the same output as the code (1)? Let's say you entered "4" as input:

(1)

    int x;
    cout << "enter integer: ";
    cin ...

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Good day to everyone.

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